The Mangement trainee is undergoing<u> Job Rotation</u>
Explanation:
- <u>Job Rotation</u> is the process of Randomly selecting people and exposing them to the various departments of the organization.
- This technique is adopted by various companies to deal with issues like job stagnation, Job Frustration,Randomness issues,High employee turnover rate .
- <u>This technique is also helpful to the organization as it helps in creation of a Talent base with Multi-Tasking Ability</u>
Primary research To get a complete picture of your target market,
Answer:
EAW = -$17,545.71
Explanation:
initial investment = $200,000
cash inflows;
- Year 1 = $33,000
- Year 2 = $44,000
- Year 3 = $55,000
- Year 4 = $66,000
- Year 5 = $77,000
- Year 6 = $88,000
- Year 7 = $99,000
- Year 8 = $110,000
- Year 9 = $132,000
cash outflows:
- Year 1 = $20,000
- Year 2 = $30,000
- Year 3 = $40,000
- Year 4 = $50,000
- Year 5 = $60,000
- Year 6 = $70,000
- Year 7 = $80,000
- Year 8 = $90,000
- Year 9 = $100,000
EAW = equivalent annual worth = equivalent annual benefits - equivalent annual costs
to determine the EAB we must first find the PV of the cash inflows using a financial calculator = $408,348.84
EAB = (PV x r) / [1 - (1 + r)⁻ⁿ] = ($408,348.84 x 10%) / [1 - (1 + 10%)⁻⁹] = $70,905.91
to determine the EAC we must first find the PV of the cash outflows (including initial outlay) using a financial calculator = $509,395
EAC = (PV x r) / [1 - (1 + r)⁻ⁿ] = ($509,395 x 10%) / [1 - (1 + 10%)⁻⁹] = $88,451.62
EAW = $70,905.91 - $88,451.62 = -$17,545.71
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Answer:
$ 74.23
Explanation:
We are given the following:
mean, μ = $ 104.50
standard deviation, σ = $ 23.62
Using the z-score table, we have
P(Z < z) = 10% (since we are evaluating lowest 10% of values)
hence P(Z < z) = 0.10
P(Z < -1.282 ) = 0.10
z = -1.282 (this evaluates to 0.1 on the z-score table)
Using z-score formula,
x = z *σ + μ
substituting the values,
x =- - 1.282 * 23.62 + 104.50
= 74.23
The most for the stock is $ 74.23