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enot [183]
2 years ago
8

What is the number of moles of hydrochloric acid will there be in 10 mL of a given solution with a molarity of 0.5 mol/L?

Chemistry
2 answers:
Elina [12.6K]2 years ago
4 0

Answer:

You are on the right track.

Explanation:

Indeed, your approach here will be to use the molar mass of aluminium hydroxide to convert the mass of the sample to moles and the mole ratio that exists between the two reactants to find the number of moles of hydrochloric acid consumed.

Al

(

OH

)

3

(

s

)

+

3

HCl

(

a

q

)

→

AlCl

3

(

a

q

)

+

3

H

2

O

(

l

)

The balanced chemical equation tells you that the reaction consumes

3

moles of hydrochloric acid and produces

3

moles of water for every

1

mole of aluminium hydroxide that takes part in the reaction.

So you can say that you have

0.75

g

⋅

the molar mass of Al

(

OH

)

3



1 mole Al

(

OH

)

3

78

g

⋅

the 1:3 mole ratio



3 moles HCl

1

mole Al

(

OH

)

3

=

0.029 moles HCl

−−−−−−−−−−−−−−

Since you know that the reaction produces the same number of moles of water as the number of moles of hydrochloric acid it consumes--the two chemical species have a

3

:

3

mole ratio in the balanced chemical equation--you can use the molar mass of water to say that the reaction will produce

0.029

moles H

2

O

⋅

18.015 g

1

mole H

2

O

=

0.52 g

−−−−−

The answers are rounded to two sig figs, the number of sig figs you have for the mass of aluminium hydroxide.

Explanation:

#<em>ClaratheBrainlyQueen</em>

Cloud [144]2 years ago
4 0

Answer: 0.005 mol

Explanation:

<u>Given information</u>

Volume = 10 mL

Molarity = 0.5 mol / L

<u>Given formula</u>

Molarity = Mole / Volume

<u>Convert volume unit to liters</u>

1 L = 1000 mL

10 mL = 10 / 1000 = 0.01 L

<u>Substitute values into the formula</u>

Molarity = Mole / Volume

Mole = Molarity × Volume

Mole = (0.5) × (0.01)

<u>Simplify by multiplication</u>

\Large\boxed{Mole~=~0.005~mol}

Hope this helps!! :)

Please let me know if you have any questions

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Sedbober [7]

Answer:

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7 0
3 years ago
How are atoms related to balancing a chemical equation?
dmitriy555 [2]

Atoms are related to balancing equations because the amount of atoms on the left of the equation (reactants) needs to be the same amount on the right (products).

For example, 2H₂ + O₂ → 2H₂O

If you count the amount of hydrogen atoms on both sides each, there would be 4 (make sure to multiply the coefficient by the subscripts).

If you count the amount of oxygen atoms on both sides each, there will be 2 of them (2 in a molecule of oxygen)

I hope this helps and please mark me as brainliest!

3 0
2 years ago
temperature is a measure of particles kinetic energy explain using words what happens to the kinetic energy as the temperature i
Vlad [161]

Answer:

More kinetic energy is gained and the particles move faster.

Explanation:

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3 0
3 years ago
Helpppppo meeeeee plzzzzzzzzz
antoniya [11.8K]
For 2 it’s 2ft 10in
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6 0
3 years ago
In Universe L, recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, quan
Advocard [28]

Answer:

Manganese, Fifth transition element

[X] 3d⁶ 4s¹

Iron, Sixth transition element

[X] 3d⁶ 4s²

Explanation:

Complete Question

In Universe L, recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, quantum mechanics works as it does in our universe, except that there are six d orbitals instead of the usual number we observe here. Use these facts to write the ground-state electron configurations of the sixth and seventh elements in the first transition series in Universe L. Note; you may use [X] to stand for the electron configuration of the noble gas at the end of the row before the first transition series.

Solution

In our universe, there are 5 d orbitals.

And according to Aufbau's principles that electrons fill the lower energy orbitals before they fill higher energy orbitals and Hund's Rule that states that electrons are fed singly to all the orbitals of a subshell before pairing occurs.

The fifth and sixth transition elements in our universe is then Manganese and Iron respectively.

Manganese - [Ar] 3d⁵ 4s²

Iron - [Ar] 3d⁶ 4s²

So, in the new universe L, where there are six d orbitals, for manganese, the fifth transition metal, because half filled orbitals are more stable than partially filled orbitals (that woukd have been rhe case if we leave 5 electrons on the 3d orbital), the 4s orbital is filled to half of its capacity and the one electron removed from the 4s is used to fill the six 3d orbital to half of its capacity too.

For the sixth transition element, the new extra electron just fills the lower energy 4s orbital, leaving the six 3d orbitals all half-filled.

Hence, they both have ground state configurations of

- Manganese, Fifth transition element

[X] 3d⁶ 4s¹

- Iron, Sixth transition element

[X] 3d⁶ 4s²

Hope this Helps!!!

7 0
3 years ago
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