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Snowcat [4.5K]
2 years ago
9

Given f(x) = 3x - 5 which statement is true? Explain how.

Mathematics
1 answer:
Ann [662]2 years ago
3 0

Answer:

(2)

Step-by-step explanation:

by substituting the values of x into f(x) and evaluating

f(0) = 3(0) - 5 = 0 - 5 = - 5 ≠ 0

f(3) = 3(3) - 5 = 9 - 5 = 4 ← True

f(4) = 3(4) - 5 = 12 - 5 = 7 ≠ 3

f(5) = 3(5) - 5 = 15 - 5 = 10 ≠ 0

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We have that:

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Then, the answer is C

<h2>Answer: C</h2>

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Answer:

Step-by-step explanation:

Let the quadratic equation of the function by the points in the given equation is,

f(x) = ax² + bx + c

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For (0, 8),

f(0) = a(0)² + b(0) + c

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For (-4, -8),

f(-4) = a(-4)² + b(-4) + 8

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-16 = 16a - 4b

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Subtract equation (1) from equation (2)

(4a - b) - (3a - b) = -4 + 6

a = 2

From equation (1),

6 - b = -6

b = 12

Function will be,

f(x) = 2x² + 12x + 8

     = 2(x² + 6x) + 8

     = 2(x² + 6x + 9 - 9) + 8

     = 2(x² + 6x + 9) - 18 + 8

     = 2(x + 3)² - 10

By comparing this function with the vertex form of the function,

y = a(x - h)² + k

where (h, k) is the vertex.

Vertex of the function 'f' will be (-3, -10)

And axis of symmetry will be,

x = -3

From the given graph, axis of the symmetry of the function 'g' is; x = -3

Therefore, both the functions will have the same axis of symmetry.

y-intercept of the function 'f' → y = 8 Or (0, 8)

y-intercept of the function 'g' → y = -2 Or (0, -2)

Therefore, y-intercept of 'f' is greater than 'g'

Average rate of change of function 'f' = \frac{f(b)-f(a)}{b-a} in the interval [a, b]

                                                               = \frac{f(-3)-f(-6)}{-3+6}

                                                               = \frac{-10-8}{3}

                                                               = -6

Average rate of change of function 'g' = \frac{g(b)-g(a)}{b-a}

                                                                = \frac{g(-3)-g(-6)}{-3+6}

                                                                = \frac{7+2}{-3+6}

                                                                = 3

Therefore, Average rate of change of function 'f' is less than 'g'.

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