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mrs_skeptik [129]
2 years ago
11

Which of the following will increase entropy in a reaction?

Chemistry
1 answer:
Lapatulllka [165]2 years ago
3 0

B. Heating up the reaction will increase the entropy of a reaction.

<h3>What is entropy?</h3>

Entropy is the measure of the degree of disorderliness of a system.

Entropy is also the measure of a system's thermal energy per unit temperature that is unavailable for doing useful work.

S = ΔH/T

where;

  • S is entropy
  • ΔH is energy input
  • T is  temperature

Entropy increases in reactions in which the total number of product molecules is greater than the total number of reactant molecules.

However, entropy increases as temperature increases. Thus, heating up the reaction will increase the entropy of a reaction.

Learn more about entropy here: brainly.com/question/6364271

#SPJ1

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You are requested to reduce the size of 50 ton/hr of a given solid. The size of the feed is such 80% passes a 4-in (76.2 mm) scr
defon

Answer:

1) The power needed to process 50 ton/hr is 135.4 HP.

2) The void fraction of the bed is 0.37.

Explanation:

1) For this type of milling operations, we can estimate the power needed for an operation according to the work index (Ei), the passing size of the circuit feed (F80) and the passing size of the product (P80).

We assume the units of Ei are kWh/t.

The equation that relates this parameters and the power is (size of particles in μm):

W=Ei*(\frac{10}{\sqrt{P80}} -\frac{10}{\sqrt{F80}} )\\\\W=9.45*(\frac{10}{\sqrt{3175\mu m}} -\frac{10}{\sqrt{76200mm}} )\\\\\\W=9.45*(0.1774+0.0362)=2.019 kWh/t

The power needed to process 50 ton/hor is

P=2.0194\frac{kWh}{Ton}*\frac{50Ton}{h}*\frac{1.341HP}{1kW}=   135.4 \, HP

2) The density of the packed bed can be expressed as

\rho=f_v*\rho_v+f_s*\rho_s

being f the fraction and ρ the density of every fraction. We know that the density of the void is 0 (ρv=0) and that fv=1-fs (the sum  of the fractions ois equal to the total space).

Then we can rearrange

\rho=f_v*\rho_v+f_s*\rho_s\\\\\rho=f_v*0+(1-f_v)*\rho_s\\\\\rho/\rho_s=1-f_v\\\\f_v=1-\rho/\rho_s=1-990/1570=1-0.63=0.37

The void fraction of the bed is 0.37.

6 0
3 years ago
In general, the more _ a metal has, the stronger its metallic bonds will be because...
Nuetrik [128]
In general, The more valence electrons a metal has, the stronger its metallic bonds will be because Boron is a metalloid and is ionically bonded.it is too electronegative to release its valence electrons for metallic bonding.As a result, their valence electrons feel a stronger pull from the nucleus (a greater effective nuclear charge) and are less easily released for metallic bonding.
5 0
3 years ago
Need help with the balancing one
DochEvi [55]
The third option, 2,2,1,2
8 0
3 years ago
C. How many moles of gas are in a container with a volume of 9.55 mL at 35 °C and a pressure of 895 mmHg?
olya-2409 [2.1K]

Answer: There are 4.45\times 10^{-4}moles of gas are in a container with a volume of 9.55 mL at 35 °C and a pressure of 895 mmHg

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 895 mm Hg= 1.18 atm  (760 mm Hg= 1 atm)

V = Volume of gas = 9.55 ml = 0.00955 L   (1 L=1000ml)

n = number of moles = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =35^0C=(35+273)K=308K

n=\frac{PV}{RT}

n=\frac{1.18atm\times 0.00955L}{0.0821L atm/K mol\times 308K}=4.46\times 10^{-4}moles

Thus there are 4.45\times 10^{-4}moles of gas are in a container with a volume of 9.55 mL at 35 °C and a pressure of 895 mmHg

5 0
3 years ago
What are families 3-12 on the periodic table called
fredd [130]

Answer:

transition elements

Explanation:

6 0
3 years ago
Read 2 more answers
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