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mrs_skeptik [129]
1 year ago
11

Which of the following will increase entropy in a reaction?

Chemistry
1 answer:
Lapatulllka [165]1 year ago
3 0

B. Heating up the reaction will increase the entropy of a reaction.

<h3>What is entropy?</h3>

Entropy is the measure of the degree of disorderliness of a system.

Entropy is also the measure of a system's thermal energy per unit temperature that is unavailable for doing useful work.

S = ΔH/T

where;

  • S is entropy
  • ΔH is energy input
  • T is  temperature

Entropy increases in reactions in which the total number of product molecules is greater than the total number of reactant molecules.

However, entropy increases as temperature increases. Thus, heating up the reaction will increase the entropy of a reaction.

Learn more about entropy here: brainly.com/question/6364271

#SPJ1

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3.44x10^2
you move the decimal over to get a single digit number with change. The number of times you move the decimal is the number for the 10 power
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What would be the new volume if the temperature on 800 mL of gas is changed
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2 years ago
How many moles of Cu(OH)2 are soluble in 1L of sodium hydroxide (NaOH) when the pH is 8.23?
Morgarella [4.7K]

Answer:

4.96E-8 moles of Cu(OH)2

Explanation:

Kps es the constant referring to how much a substance can be dissolved in water. Using Kps, it is possible to know the concentration of weak electrolytes. Then, pKps is the minus logarithm of Kps.

Now, we know that sodium hydroxide (NaOH) is a strong electrolyte, who is completely dissolved in water. Therefore the pH depends only on OH concentration originating from NaOH. Let us to figure out how much is that OH concentration.

pH= -log[H]\\pH= -log (\frac{kw}{[OH]})

8.23 = - log(\frac{Kw}{[OH]} \\10^{-8.23} = Kw/[OH]\\ [OH] = Kw/10^{-8.23}

[OH]=1.69E-6

This concentration of OH affects the disociation of Cu(OH)2. Let us see the dissociation reaction:

Cu(OH)_2 -> Cu^{2+} + 2OH^-

In the equilibrum, exist a concentration of OH already, that we knew, and it will be added that from dissociation, called "s":

The expression for Kps is:

Kps= [Cu^{2+}] [OH]^2

The moles of (CuOH)2 soluble are limitated for the concentration of OH present, according to the next equation.

Kps= s*(2s+1.69E-6)^2

"s" is the soluble quantity of Cu(OH)2.

The solution for this third grade equation is s=4.96E-8 mol/L

Now, let us calculate the moles in 1 L:

moles Cu(OH)_2 = 4.96E-8 mol/L * 1 L = 4.96E-8 moles

7 0
3 years ago
How many moles of KOH are needed to neutralize 1.5 moles of H2SO4 ​
kap26 [50]

Answer:

1.5 moles of H₂SO₄ needs 3.0 moles pf KOH to be neutralized.​

Explanation:

  • KOH is dissociate according to the equation:

KOH → K⁺ + OH⁻.

  • H₂SO₄ is dissociated according to the equation:

H₂SO₄ → 2H⁺ + SO₄²⁻.

<em>So, every 1.0 mole of KOH produces 1.0 mol of OH⁻.</em>

<em>While, every 1.0 mole of H₂SO₄ produces 1.0 mol of H⁺.</em>

<em />

Thus, every mol of H₂SO₄ needs 2.0 moles of KOH to be neutralized.

<em>So, 1.5 moles of H₂SO₄ needs (2 x 1.5 mol) = 3.0 moles pf KOH to be neutralized.​</em>

4 0
3 years ago
Percent dissociation of a particular solute depends on _____. Select all that apply.
Novosadov [1.4K]
Temprature is the correct one
6 0
3 years ago
Read 2 more answers
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