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notka56 [123]
3 years ago
6

The heat required to raise the temperature of 12g of water from 16 C to 21 C is:

Chemistry
2 answers:
sergey [27]3 years ago
6 0
132 is the answer you’re welcome
alukav5142 [94]3 years ago
3 0

Answer:

The answer is 132

Explanation:

You might be interested in
Need these 2 answered asap pls
Kitty [74]

Answer:

im not a brain wiz but i think 20

Explanation:

3 0
3 years ago
How many molecules are in 4.62 moles of nitric acid (HNO3)?
Lena [83]

Answer:

2.8x10^24

Explanation:

To convert moles to molecules, multiply the number of moles by Avagadro's number (6.02x10^23. Round if required.

4.62mol × 6.02x10^23 = 2.8x10^24

6 0
3 years ago
Sort each of the following elements by effective nuclear charge, Zeff, from smallest to largest:
krek1111 [17]

Answer:

Rb = +1 , Sr = +2, In= +3,  Sn = +4, Sb= +5

Explanation:

Formula:

Zeff = Z - S

Z = atomic number

S = number of core shell or inner shell electrons

For Sn:

Electronic configuration:

Sn₅₀ = [Kr] 4d¹⁰ 5s² 5p²

Zeff = Z - S

Zeff = 50 - 46

Zeff = +4

For Rb:

Electronic configuration:

Rb₃₇ = [Kr] 5s¹

Zeff = Z - S

Zeff = 37 - 36

Zeff = +1

For Sb:

Electronic configuration:

Sb₅₁ = [Kr] 4d¹⁰ 5s² 5p³

Zeff = Z - S

Zeff = 51 - 46

Zeff = +5

For In:

Electronic configuration:

In₄₉ = [Kr] 4d¹⁰ 5s² 5p¹

Zeff = Z - S

Zeff = 49 - 46

Zeff = +3

For Sr:

Electronic configuration:

Sr₃₈= [Kr]  5s²

Zeff = Z - S

Zeff = 38 - 36

Zeff = +2

8 0
4 years ago
In the reaction h2so4 + na2co3 → na2so4 + co2 + h2o 14.5 g of water is collected. what is the molarity of sulfuric acid if 1.78
Yuliya22 [10]
H2SO4 + Na2CO3  → Na2SO4 + CO2 + H2O

The molarity  of  sulfuric acid  if  1.78  L  were used  in the   above reaction is
 0.453 M  (answer 2)

      Calculation
find the  moles of water  produced  = mass/molar  mass

=   14.5 g /18 g/mol  = 0.806  moles

by use of of mole ratio  between  H2So4  to H2O   which is 1:1  the    moles    of   H2SO4   is also =  0.806   moles


Molarity  of H2SO4 is therefore =    moles/volume  in   liters

=  0.806   mol/  1.78 L  =  0.453 M (answer 2)
8 0
3 years ago
AlF3 is almost insoluble in anhydrous HF but dissolves if KF is present.passage of BF3 through the resulting solution causes AlF
miskamm [114]
<span>It's because the product formed with BF3 is more complex which able to decompose AlF3.

</span>AlF3 doesn't dissolve in HF because of the fluorine. It's doesn't allow for coordination due to the hydrogen. However, it will dissolve in KF. If you look at the chemical reaction, it's able to form a salt.

<span>3KF+Al<span>F3</span>−>3KF.Al<span>F3</span></span>
4 0
4 years ago
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