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notka56 [123]
3 years ago
6

The heat required to raise the temperature of 12g of water from 16 C to 21 C is:

Chemistry
2 answers:
sergey [27]3 years ago
6 0
132 is the answer you’re welcome
alukav5142 [94]3 years ago
3 0

Answer:

The answer is 132

Explanation:

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Outside wooden steps may get slippery when they are wet. How could you make them less<br> slippery?
IceJOKER [234]

Answer:

By adding a surface that increases friction? Such as outdoor mats(rough ones), which increases friction between the bottom of the boots and the surface.

7 0
3 years ago
What are the smallest sub atomic structure
Anton [14]

Answer:

Electrons

Explanation:

In an atom there would be three subatomic particles: Neutrons, electrons, protons. The smallest and lightest in terms of mass is electrons. This is because the nucleus is comprised of the protons and the neutrons, these have a greater mass than electrons as electrons has very little mass that can considered to be 0.

7 0
3 years ago
What volume does .0685 mol of gas occupy at STP? 1mole =22.4
GuDViN [60]
V = nRT/P
V = 0.685 mol*(.0821 L*atm/K*mol)*273 K/1 atm
4 0
3 years ago
Read 2 more answers
A thermometer is placed in a beaker full of water that has been sitting on the lab table for a few hours. The beaker is placed o
krek1111 [17]
Based on the information I would assume B, 73 degrees...

It shouldn't be A, 4 minutes on the burner should increase the temperature.

If it were D, it would be beyond boiling, and water takes a decent amount of energy to heat, D should be all vapor.

Same logic for C, it's basically almost boiling.

I would say 73 degrees seems most reasonable for 4 minutes.
7 0
4 years ago
Read 2 more answers
Calculate the following quantity: molarity of a solution prepared by diluting 45.45 mL of 0.0404 M ammonium sulfate to 550.00 mL
dybincka [34]

Answer:

M_2=3.34x10^{-3}M

Explanation:

Hello!

In this case, since a dilution process implies that the moles of the solute remain the same before and after the addition of diluting water, we can write:

M_1V_1=M_2V_2

Thus, since we know the volume and concentration of the initial sample, we compute the resulting concentration as shown below:

M_2=\frac{M_2V_2}{V_1} =\frac{45.45mL*0.0404M}{550.00mL}\\\\M_2=3.34x10^{-3}M

Best regards!

5 0
3 years ago
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