The heat of fusion (δhfus) of benzene (c6h6) is 10. 0kjmol while its heat of vaporization (δhvap) is 34. 1kjmol then enthalpy of sublimation (δhsub) of benzene is 44.1 kJ mol.
The heat of fusion is amount of heat involved during conversion of solid into liquid.
Solid → liquid
The heat of vaporization is amount of heat involved during conversion of liquid into vapor.
liquid → vapor
The enthalpy of sublimation is amount of energy involved during conversion of solid into vapor.
Solid → vapor
The enthalpy of sublimation is equal to sum of heat of fusion and heat of vaporization .
Mathematically, heat of sublimation = heat of fusion + heat of vaporization .
heat of sublimation = 10. 0 kJmol + 34. 1 kJmol. = 44.1 kJ mol
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