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Sidana [21]
4 years ago
13

Why does knowing the mass of an object not help you identify what material the object is made from?

Chemistry
1 answer:
jeka57 [31]4 years ago
4 0
Because mass is not always the same for objects made from the same material. Just because an object has the same mass as another doesn’t mean they are the same material.
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Similarities of ancient and modern philosophy​
quester [9]
A big difference is that for the Greeks philosophy was almost a fresh start. For us, doing philosophy cannot avoid taking into consideration what the great thinkers of the past have thought (or how they have thought).
7 0
3 years ago
As current flows through a system, what happens to the voltage available at each load?
navik [9.2K]

Answer: voltage drops in each resistor ΔU= RI

Explanation: if lamps or other resistor which cause load are in series in

Electric circuit, current I passing circuit is same. Voltage decreases

In every resistor

3 0
3 years ago
how much heat is released when 70.9g of water at 66C cools to 25C? The specific heat of water is 1 cal/gC
Serga [27]

Answer:

-12162.47 joules (or -12000 joules when accounting for significant figures)

Explanation (btw I used 1 cal as 4.184 joules because SI units are better):

q = m c delta T

q = (70.9) (4.184) (25 - 66)  

q = (70.9) (4.184) (-41)

q = -12162.47 joules

7 0
3 years ago
Answer the following question for this equation: 2H2 + O2 → 2H2O
kondaur [170]

Answer:

B. 1:2

Explanation:

Molar ratio depicts the relationship between the number of moles of two substances. The chemical equation in this question is as follows:

2H2 + O2 → 2H2O

This question is asking to identify the molar ratio of O2 to H2O in the equation. Since 1 mole of oxygen gas (O2) produces 2 moles of water (H2O). Hence, the O2 to H2O molar ratio is 1:2.

6 0
3 years ago
A sample of octane (c8h18 that has a mass of 0.750 g is burned in a bomb calorimeter. as a result, the temperature of the calori
timurjin [86]
In a closed system, heat should be conserved which means that the heat produced in the calorimeter is equal to the heat released by the combustion reaction. We calculate as follows:

Heat of the combustion reaction = mC(T2-T1)
                                                          = 1 (1.50) (41-21)
                                                          = 30 kJ
7 0
3 years ago
Read 2 more answers
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