Answer:
1.4952 grams of sodium bicarbonate she would need to ingest to neutralize this much HCl.
Explanation:
![Moles (n)=Molarity(M)\times Volume (L)](https://tex.z-dn.net/?f=Moles%20%28n%29%3DMolarity%28M%29%5Ctimes%20Volume%20%28L%29)
Moles of hydrochloric acid = n
Volume of hydrochloric acid solution = 200.0 mL = 0.200 L
Molarity of the hydrochloric acid = 0.089 M
of HCL
![HCl(aq)+NaHCO_3(aq)\rightarrow NaCl(aq)+H_2O(l)+CO_2(g)](https://tex.z-dn.net/?f=HCl%28aq%29%2BNaHCO_3%28aq%29%5Crightarrow%20NaCl%28aq%29%2BH_2O%28l%29%2BCO_2%28g%29)
According to reaction, 1 mole of HCl is neutralized by 1 mole of sodium bicarbonate.
Then 0.0178 moles of HCl wil be neutralized by :
of sodium bicarbonate
Mass of 0.0178 moles of sodium bicarbonate:
0.0178 mol × 72 g/mol = 1.4952 g
1.4952 grams of sodium bicarbonate she would need to ingest to neutralize this much HCl.
Explanation:
It is given that,
The time period of artificial satellite in a circular orbit of radius R is T. The relation between the time period and the radius is given by :
![T^2\propto R^3](https://tex.z-dn.net/?f=T%5E2%5Cpropto%20R%5E3)
The radius of the orbit in which time period is 8T is R'. So, the relation is given by :
![(\dfrac{T}{T'})^2=(\dfrac{R}{R'})^3](https://tex.z-dn.net/?f=%28%5Cdfrac%7BT%7D%7BT%27%7D%29%5E2%3D%28%5Cdfrac%7BR%7D%7BR%27%7D%29%5E3)
![\dfrac{1}{64}=(\dfrac{R}{R'})^3](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B64%7D%3D%28%5Cdfrac%7BR%7D%7BR%27%7D%29%5E3)
![R'=4\times R](https://tex.z-dn.net/?f=R%27%3D4%5Ctimes%20R)
So, the radius of the orbit in which time period is 8T is 4R. Hence, this is the required solution.
Answer:
no
Explanation:
Because gravity is necessary for density differences to arise, convection wouldn't happen in a zero-gravity environment such as space.