Predict the chemical formula for the ionic compound formed by NH4+ and POsub4exponent3-

Which of the following are the types of RNA?

Andrew [12]

Answer:

Explanation:

Of the numerous sorts of RNA, the three most well-known and most commonly examined are delivery person RNA (mRNA), exchange RNA (tRNA), and ribosomal RNA (rRNA), which are show in all living beings. These and other sorts of RNAs essentially carry out biochemical responses, comparative to proteins.

5 0

3 years ago

Read 2 more answers

How many protons and neutrons are in the nucleus of isotope with mass of 68.926 amu?

Sidana [21]

There are 30 protons and 39 neutrons in the nucleus.

This must me the isotope of an element with an atomic mass close to 69 u.
The only candidates are Zn and Ga.
Zn has a zinc-69 isotope with mass 68.926 u.
Ga has a gallium -69 isotope with mass 68.925 u.
The isotope is probably $_{30} ^{69}Zn$ .
It has 30 protons and 39 neutrons.

4 0

2 years ago

For the reaction a2 + b2 → 2ab, ea(fwd) = 105 kj/mol and ea(rev) = 77 kj/mol. assuming the reaction occurs in one step, calculat

Lady bird [3.3K]

Answer is: 28 kJ.
Chemical reaction: A₂ + B₂ ⇄ 2AB.
Ea(forward) = 105 kJ/mol.
Ea(reverse) = 77 kJ/mol.
ΔH(reaction) = ?
The enthalpy change of reaction is the change in the energy of the reactants to the products.
ΔH(reaction) = Ea(forward) - Ea(reverse).
ΔH(reaction) = 105 kJ/mol - 77 kJ/mol.
ΔH(reaction) = 28 kJ/mol; this is endothermic reaction (ΔH > 0).

6 0

3 years ago

Given that cao(s) + h2o(l) → ca(oh)2(s), δh°rxn = –64.8 kj/mol, how many grams of cao must react in order to liberate 525 kj of

USPshnik [31]

Answer:

454.3 g.

Explanation:

From the given data:

1.0 mol of CaO liberates → – 64.8 kJ.

??? mol of CaO liberates → - 525 kJ.

∴ The no. of moles needed = (1.0 mol)(- 525 kJ)/(- 64.8 kJ) = 8.1 mol.

∴ The no. of grams of CaO needed = no. of moles x molar mass = (8.1 mol)(56.077 g/mol) = 454.3 g.

8 0

2 years ago

Write the net ionic equation for the reaction of aqueous solutions of ammonium chloride and iron(III) hydroxide.

vagabundo [1.1K]

Answer:

$Fe(OH)_3(s)\rightarrow Fe^{3+}(aq)+3OH^-(aq)$

Explanation:

Hello.

In this case, for the reaction between aqueous solutions of ammonium chloride and iron (III) hydroxide, we have the following complete molecular reaction:

$3NH_4Cl(aq)+Fe(OH)_3(s)\rightarrow 3NH_4OH+FeCl_3$

And the full ionic equation, taking into account that the iron (III) hydroxide cannot be dissolved as it is insoluble in water:

$3NH_4^+(aq)+3Cl^-(aq)+Fe(OH)_3(s)\rightarrow 3NH_4^+(aq)+3OH^-(aq)+Fe^{3+}(aq)+3Cl^-(aq)$

Finally, the net ionic equation, considering that spectator ions are NH₄⁺, Cl⁻ as they are both the left and right side, therefore, the net ionic equation is:

$Fe(OH)_3(s)\rightarrow Fe^{3+}(aq)+3OH^-(aq)$

Best regards.

8 0

2 years ago