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Bad White [126]
1 year ago
5

Number of oxygen atoms in 16 g of So2??​

Chemistry
1 answer:
kotykmax [81]1 year ago
6 0

Now , we know that one mole of SO² Contains 2 Moles ( two ) of atoms of oxygen . Hence , 16 Grams of SO² Contains 0.5 Mole(s) of Oxygen

0.5

hope this helps you. :)

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Why do different chemicals emit different colors of light?​
Mama L [17]

Answer:

Because no two elements have the same set of energy levels, different elements emit different colors of light. Energy is released when electrons move from higher energy levels to lower ones (visible light).

Explanation:

5 0
3 years ago
Write the full ground state electron configuration of f+.
ANTONII [103]

Answer:- 1s^22s^22p^4 .

Explanation:- Atomic number for fluorine(F) is 9 and it's electron configuration is 1s^22s^22p^5 . F^+ is formed when F loses one electron from it's valence shell.

F\rightarrow F^++1e^-

Second shell is the valence shell for fluorine and so it loses one electron from 2p to form  F^+  and the electron configuration of the ion becomes 1s^22s^22p^4 .


7 0
3 years ago
H2(g) + F2(g) → 2 HF(g) ΔH=-546 kJ
Arisa [49]

Answer: help please !!

Explanation:

4 0
3 years ago
Read 2 more answers
The estimated heat of vaporization of diethyl ether using the Chen's rule is A. 29.7 KJ/mol B. 33.5 KJ/mol C. 26.4 KJ/mol D. 36.
Brums [2.3K]

Answer:

C. 26.4 kJ/mol

Explanation:

The Chen's rule for the calculation of heat of vaporization is shown below:

\Delta H_v=RT_b\left [ \frac{3.974\left ( \frac{T_b}{T_c} \right )-3.958+1.555lnP_c}{1.07-\left ( \frac{T_b}{T_c} \right )} \right ]

Where,

\Delta H_v is the Heat of vaoprization (J/mol)

T_b is the normal boiling point of the gas (K)

T_c is the Critical temperature of the gas (K)

P_c is the Critical pressure of the gas (bar)

R is the gas constant (8.314 J/Kmol)

For diethyl ether:

T_b=307.4\ K

T_c=466.7\ K

P_c=36.4\ bar

Applying the above equation to find heat of vaporization as:

\Delta H_v=8.314\times307.4 \left [ \frac{3.974\left ( \frac{307.4}{466.7} \right )-3.958+1.555ln36.4}{1.07-\left ( \frac{307.4}{466.7} \right )} \right ]

\Delta H_v=26400 J/mol

The conversion of J into kJ is shown below:

1 J = 10⁻³ kJ

Thus,

\Delta H_v=26.4 kJ/mol

<u>Option C is correct</u>

6 0
3 years ago
Which would be attracted most to a magnet?
Debora [2.8K]
Either iron or metal
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