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1 year ago

How does betelgeuse compare to the other stars in the amount of light it is giving off?

1 answer:

7 0

Betelgeuse is the 10th brightest star in the night sky comparing to other stars. And it is the second brightest in Orion's constellation.

Betelgeuse is the tenth brightest star in the night sky and, after Rigel, the second brightest in Orion's constellation. it is a distinctly reddish semiregular variable star with the widest apparent magnitude range of any first-magnitude star, ranging from +0.0 to +1.6. Betelgeuse is the brightest star in the night sky at near - infrared wavelengths. Its Bayer name is Orionis, which is Latinized to alpha Orionis and abbreviated alpha Ori or Ori

learn more about Betelgeuse star from here : brainly.com/question/14527447

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Explain the relationship between schemas and stereotypes

natka813 [3]

ok i know what your talking about

6 0

2 years ago

If a car has a mass of 200 kilograms and produces a force of 500 N, how fast will the car accelerate?

Hitman42 [59]

Answer:

2.5m/s²

Explanation:

Given parameters:

Mass of car = 200kg

Force on car = 500N

Unknown:

Acceleration of the car = ?

Solution:

According to Newton's second law of motion:

Force = mass x acceleration

Insert the given parameters and find the acceleration;

500 = 200 x acceleration

acceleration = 2.5m/s²

3 0

2 years ago

Read 2 more answers

A 1200-kg car initially at rest undergoes constant acceleration for 8.8 s, reaching a speed of 10 m/ s. It then collides with a

atroni [7]

Answer:

The final kinetic energy of the two-car system is 60,000 J.

Explanation:

Given;

mass of the car, m = 1200 kg

time of motion, t = 8.8 s

final velocity of the car, v = 10 m/s

Apply the principle of conservation of kinetic energy; the initial kinetic energy is equal final kinetic energy.

$K.E_i = K.E_f\\\\K.E_f = \frac{1}{2}mv^2\\\\K.E_f = \frac{1}{2}(1200)(10)^2\\\\K.E_f = 60,000 \ J$

Therefore, the final kinetic energy of the two-car system is 60,000 J.

4 0

2 years ago

A truck pushes a mound of dirt 5 meters with a force of 75 newtons. How much work has been done ?

Paladinen [302]

Work = force × distance, assuming that the force is parallel to displacement.

Work L=75×5=375J

6 0

2 years ago

1 m is equivalent to how many centimeters in the metric system

gladu [14]

100. A centimeter is a 100th of a meter.

5 0

2 years ago