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ikadub [295]
3 years ago
12

A 1200-kg car initially at rest undergoes constant acceleration for 8.8 s, reaching a speed of 10 m/ s. It then collides with a

stationary car that has a perfectly elastic spring bumper. What is the final kinetic energy of the two-car system
Physics
1 answer:
atroni [7]3 years ago
4 0

Answer:

The final kinetic energy of the two-car system is 60,000 J.

Explanation:

Given;

mass of the car, m = 1200 kg

time of motion, t = 8.8 s

final velocity of the car, v = 10 m/s

Apply the principle of conservation of kinetic energy; the initial kinetic energy is equal final kinetic energy.

K.E_i = K.E_f\\\\K.E_f = \frac{1}{2}mv^2\\\\K.E_f =  \frac{1}{2}(1200)(10)^2\\\\K.E_f = 60,000 \ J

Therefore, the final kinetic energy of the two-car system is 60,000 J.

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Gala2k [10]

the correct answer is c

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Answer : B - real

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8 0
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7. A 78-kg skydiver has a speed of 62 m/s at an altitude of 870 m above the ground.
miv72 [106K]

The kinetic energy, potential energy and total mechanical energy possessed by the skydriver are 1.5 × 10⁵ Joule, 6.7 × 10⁵ Joule and 8.2 × 10⁵ Joule respectively.

To find the answer, we need to know about the expression of kinetic energy and potential energy.

<h3>What are the expressions of kinetic energy and potential energy?</h3>
  • Mathematically, kinetic energy= 1/2 × mass × velocity²
  • Gravitational potential energy near the earth surface= mass × g × height on the earth surface

<h3>What's the kinetic energy, potential energy and total mechanical energy of the 78kg skydriver at 870 m on earth surface with 62 m/s velocity?</h3>
  • Kinetic energy= 1/2 × 78 × 62² = 1.5 × 10⁵ Joule
  • Potential energy= 78×9.8×870= 6.7× 10⁵ Joule
<h3>What's the total mechanical energy?</h3>
  • Mechanical energy= kinetic energy+ potential energy
  • 1.5 × 10⁵ Joule + 6.7× 10⁵ Joule = 8.2× 10⁵ Joule

Thus, we can conclude that the kinetic energy, potential energy and total mechanical energy possessed by the skydriver are 1.5 × 10⁵ Joule, 6.7 × 10⁵ Joule and 8.2 × 10⁵ Joule respectively.

Learn more about the kinetic energy, potential energy and mechanical energy here:

brainly.com/question/17051553

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8 0
2 years ago
Just after a motorcycle rides off the end of a ramp and launches into the air, its engine is turning counterclockwise at 8325 re
alexgriva [62]

Answer:

\frac{Ie}{lm} = 1.10*10^{-3}

Explanation:

GIVEN DATA:

Engine operating speed nf = 8325 rev/min

engine angular speed ni= 12125 rev/min

motorcycle angular speed N_m= - 4.2 rev/min

ratio of moment of inertia of engine to motorcycle is given as

\frac{Ie}{lm} = \frac{-N}{(nf-ni)}

\frac{Ie}{lm} = \frac{-(-4.2)}{(12125 - (8325))}

\frac{Ie}{lm} = 1.10*10^{-3}

5 0
4 years ago
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damaskus [11]
<span>The Earth’s orbit is a nearly circular ellipse.
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The Earth moves around the Sun in an orbit that is almost but not quite circular. As Kepler proved in the seventeenth century, the orbit is actually an ellipse. A parameter called the eccentricity (e) defines the degree of departure from a circle. A value of e=0 would indicate a circle whereas a value of e=0.9 would indicate a very elongated ellipse. The eccentricity of the Earth's orbit is currently e=0.0167.
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