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ikadub [295]
2 years ago
12

A 1200-kg car initially at rest undergoes constant acceleration for 8.8 s, reaching a speed of 10 m/ s. It then collides with a

stationary car that has a perfectly elastic spring bumper. What is the final kinetic energy of the two-car system
Physics
1 answer:
atroni [7]2 years ago
4 0

Answer:

The final kinetic energy of the two-car system is 60,000 J.

Explanation:

Given;

mass of the car, m = 1200 kg

time of motion, t = 8.8 s

final velocity of the car, v = 10 m/s

Apply the principle of conservation of kinetic energy; the initial kinetic energy is equal final kinetic energy.

K.E_i = K.E_f\\\\K.E_f = \frac{1}{2}mv^2\\\\K.E_f =  \frac{1}{2}(1200)(10)^2\\\\K.E_f = 60,000 \ J

Therefore, the final kinetic energy of the two-car system is 60,000 J.

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denpristay [2]

Answer:

c. 1600J

Explanation:

The loss in potential energy of the boy is given by:

U=mg \Delta h

where

m = 40 kg is the mass of the boy

g = 9.8 m/s^2 is the acceleration of gravity

\Delta h = 4 m + 0.02 m = 4.02 m is the total change in the height of the boy (4 metres + 2 cm due to the compression of the spring)

Substituting, we find

\Delta U = (40 kg)(9.8 m/s^2)(4.02 m) = 1577 J \sim 1600 J

4 0
2 years ago
Which of these planets is the odd one out based on their physical features?
Maurinko [17]

Answer:

mars

Explanation:

the planet that is the odd is Mars

7 0
2 years ago
Heisenberg's Uncertainty Principle states that we cannot simultaneously measure both the position and momentum of an object bett
ankoles [38]

For this specific problem, the photons have been localized to D<span>x = </span>0.027m uncertainty. I am hoping that this answer has satisfied your query about and it will be able to help you, and if you’d like, feel free to ask another question.

5 0
3 years ago
A photographer wants to determine the color of light he can use in the darkroom that will not expose the films he is processing.
Sonbull [250]

For a photographer that wishes to determine the color of light that he can use in a dark room that will not expose the films he is processing, having used a Blue Incandescent bulb, he should proceed to use a Red Incandescent bulb for the next trial.

The photographer in question is performing an experiment. For these kinds of experiments it is important to identify the variables present, which can be of three kinds:

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  2. Dependent variables
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For this experiment, the dependent variable is the exposure of the light onto the films, given that this is what we wish to measure. The independent variable will be the color of the light being used which is what will affect the dependent variable.

The remaining variable must be the control variable. Unlike the previous variables, we can have more than one of these. The control variable is there to make sure that only the dependent variable is affecting the outcome. We do this by keeping the control variable the same through each trial, which is why the photographer should not change the type of bulb in the second experiment, changing only the color of the light.

To learn more visit:

brainly.com/question/1549017?referrer=searchResults

4 0
2 years ago
PLEASE HELP ASAP WILL GIVE BRAINLIEST!!!!
nydimaria [60]

Explanation:

Please mark me as the brainliest answer

7 0
2 years ago
Read 2 more answers
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