A mechanic pushes a 3540 kg car from rest to a speed of v, doing 4864 J of work in the process. Find the speed v. Neglect fricti
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Answer:
Energy needed = 54.02 J
Explanation:
the Energy in an elastic spring from hookes law is given as
F= ke , therefore the energy (E) is
E =
K = 19.5 N/cm
e = 1.39cm
E = x 19.5 x 1.39
E = 13.55 J
The energy to stretch the spring for 6.93cm is
E = x 19.5 x 6.93
E = 67.57 J
The more energy needed for the further stretch is
67.57 - 13.55
Energy needed = 54.02 J
To solve this exercise it is necessary to apply the concepts related to Robert Boyle's law where:
Where,
P = Pressure
V = Volume
T = Temperature
n = amount of substance
R = Ideal gas constant
We start by calculating the volume of inhaled O_2 for it:
Our values are given as
P = 1atm
T=293K
Using the equation to find n, we have:
Number of molecules would be found through Avogadro number, then