If i am not mistake u can use -log[concentration of oh-] to find it
ie -log[6.4*10^-10]=9.19
The answer is A. Table salt is a pure substance.
10g/ 763g/mol= 0.013moles
Answer:
1.25 gram of cesium-137 will remain.
Explanation:
Given data:
Half life of cesium-137 = 30 year
Mass of cesium-137 = 5.0 g
Mass remain after 60 years = ?
Solution:
Number of half lives passed = Time elapsed / half life
Number of half lives passed = 60 year / 30 year
Number of half lives passed = 2
At time zero = 5.0 g
At first half life = 5.0 g/2 = 2.5 g
At 2nd half life = 2.5 g/ 2 = 1.25 g
Thus. 1.25 gram of cesium-137 will remain.
The correct options would be
OPTIONS 1 & 2
The state which a person lives in has nothing to do with the experiment, although it would most likely make it easier to observe. Wheter they develop heart disease or not is the results of the experiment.