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Marat540 [252]
3 years ago
10

Chemistry help please!! ​

Chemistry
1 answer:
Galina-37 [17]3 years ago
7 0

Answer:

no so boring........................

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PLEASE ANSWER ASAP 30PTS<br><br> How can you determine and object’s mechanical energy ?
pychu [463]
Mechanical energy of a body is simply the combination of its kinetic energy and potential energy
3 0
3 years ago
The compound 1-Butene is modeled here.
Grace [21]

Answer:

             Option-A. Covalent bonds would need to form between the molecules.

Explanation:

                   In given statement the molecules of 1-Butene are adding to each other forming a macromolecule called as Polybutene. Such type of reactions are called Polymerization reactions.

                   Polymerization reactions are those reactions in which small molecules called as monomers join together to form a large molecule also known as polymers. These reactions are done via different mechanisms like addition reaction, condensation reactions e.t.c.

Example:

              Polybutene (polymer) is made up of 1-butene (monomers) through addition reaction in which the double bonds of 1-butene molecules are involved in the formation of new single covalent bond via acid catalyzed, base catalyzed or free radical mechanisms.

                           n H₂C=CH-CH₂-CH₃    →    --[H₂C-CH(C₂H₅)]-n--

In above equation "n" represent large number, H₂C=CH-CH₂-CH₃ represent 1-Butene (monomer) and --[H₂C-CH(C₂H₅)]-n-- represent polybutene (polymer).

6 0
3 years ago
Be sure to answer all parts. for each reaction, find the value of δso. report the value with the appropriate sign. (a) 3 no2(g)
Maurinko [17]

Answer:

Change in entropy for the reaction is

ΔS° = -268.13 J/K.mol

Explanation:

To calculate the change in entropy for the balanced reaction, we require the natural entropy of all the reactants and products in the reaction.

3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)

From Literature.

S°(NO₂) = 240.06 J/K.mol

S°(H₂O) = 69.91 J/K.mol

S°(HNO₃) = 155.60 J/K.mol

S°(NO) = 210.76 J/K.mol

These are the entropies of the reactants and products under standard conditions of 298.15 K and 1 atm.

Note that

ΔS° = Σ nᵢS°(for products) - Σ nᵢS°(for reactants)

Σ nᵢS°(for products) = [2 × S°(HNO₃)] + [1 × S°(NO)]

= (2 × 155.60) + (1 × 210.76) = 521.96 J/K.mol

Σ nᵢS°(for reactants) = [3 × S°(NO₂)] + [1 × S°(H₂O)]

= (3 × 240.06) + (1 × 69.91) =790.09 J/K.mol

ΔS° = Σ nᵢS°(for products) - Σ nᵢS°(for reactants)

ΔS° = 521.96 - 790.09 = -268.13 J/K.mol

Hope this Helps!!

4 0
3 years ago
Which of the following is an indication that a substance has undergone a chemical change?
Anna [14]

Physical change is a change in size, shape, state or solution. You still have the same material.

Chemical change forms a new substance. It can be seen by a color change, odor change, gas formation, precipitate formation or large change in energy.

Hope it helps
4 0
3 years ago
Read 2 more answers
Ba(oh)2+H3po4+h2o how is it <br> balance ?
Igoryamba

Answer:

3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + 6H2O

Explanation:

Ba(OH)2 + H3PO4 —> Ba3(PO4)2 + H2O

There are 3 atoms of Ba on the right side and 1atom on the left side. It can be balance by putting 3 in front of Ba(OH)2 as shown below:

3Ba(OH)2 + H3PO4 —> Ba3(PO4)2 + H2O

There are 2 atoms of P on the right side and 1atom on the left. It can be balance by putting 2 in front of H3PO4 as shown below:

3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + H2O

Now, there are a total of 12 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 6 in front of H2O as shown below:

3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + 6H2O

Now the equation is balanced as the numbers of the atoms of the different elements present on both sides are equal

4 0
4 years ago
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