The linear equation is y = -x - 6
Step-by-step explanation:
To form a linear equation from two points lie on the line which the equation represented it
- Find the slope of the line by using the formula

- Then use the slope-intercept form of the equation y = m x + b
- To find the value of b substitute x and y of the equation by the coordinates of one of the two given points
∵ Points (-2 , -4) and (-3 , -3) lie on the line
∴
= -2 and
= -3
∴
= -4 and
= -3
- Substitute these values in the formula of the slope
∵ 
∴ m = -1
∵ The form of the equation is y = m x + b
∵ m = -1
∴ y = (-1) x + b
∴ y = -x + b
To find b substitute x and y in the equation by the coordinates of
point (-2 , -4) OR (-3 , -3)
∵ x = -3 and y = -3
∴ -3 = -(-3) + b
∴ -3 = 3 + b
- Subtract 3 from both sides
∴ -6 = b
∴ The equation is y = -x + (-6)
∴ y = -x - 6
The linear equation is y = -x - 6
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Using distance formula =√<span>(5-3)sq+(1-4)sq
=</span>√4+9
=√13
<span>Consider a angle â BAC and the point D on its defector
Assume that DB is perpendicular to AB and DC is perpendicular to AC.
Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC
Proof
Consider triangles ΔADB and ΔADC
Both are right angle, â ABD= â ACD=90 degree
They have congruent acute angle â BAD and â CAD( since AD is angle bisector)
They share hypotenuse AD
therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>