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3 years ago

Another 100 points time is running out this has to be correct! Correct answer gets brainiest! Hurry!

Physics

2 answers:

ioda3 years ago

6 0

Answer:

I think it is 30km/hr ooh

FromTheMoon [43]3 years ago

4 0

<h2>Hey there! </h2>

<h3>I guess the answer will be 30 km/h</h3>

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a value of pH 7.0 indicates A) a zero hydrogen-ion concentration B) the lowest hydrogen-ion concentration C) the highest hydroge

pychu [463]

The Answer is D) equal hydrogen and hydroxide-ion concentration

4 0

4 years ago

Suppose a 96.10 kg hiker has ascended to a height of 1841 m above sea level in the process of climbing Mt. Washington. By what p

lbvjy [14]

Answer:

0.029%

Explanation:

Weight on the surface is given by,

$F_W = mg = (96.1Kg)(9.8m/s^2)=941.78N$

The acceleration due to gravity at given height is,

$g_h=\frac{gR^2}{R+h^2}$

The weight in another height is equal to

$F_h=mg_h$

$F_h= m*\frac{gR^2}{R+h^2}$

$F_h = \frac{F_WR^2}{(R+h)^2}$

$F_h=\frac{(941.78)(6.371*10^6)}{(6.371*10^6+1841)}$

$F_h = 941.50N$

The change of the Weight is,

$\frac{F-F_h}{F}*100=\frac{941.78-941.50}{941.78}*100=0.029\%$

6 0

3 years ago

Three moles of an ideal gas are taken around the eyele acb shown in Fig.For this gas Co-29.2J/mol-K.Process ac is at constant pr

Scorpion4ik [409]

For three moles of an ideal gas are taken around the eye, the total work for the cycle is mathematically given as

Wt=1945.475J

<h3>What is the total work F for the cycle.(R=8.31J/molK)?</h3>

Generally, the equation for work is mathematically given as

Wt=wac+Wc+Wba

Therefore

Wac=Pa(Vc-Va)=nR(Tc-Ta)

Wac=3(8.314*192)

Wac=4788.864J

Wcb=P1v1-p2v2/v-1

Wcb-3*8.34*108/0.4

Wcb=-6734.34J

Wab=0

In conclusion,

Wt=wac+Wc+Wba

Wt=4788.864J+0+(-6734.34J)

Wt=+1945.475J

Read more about work

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8 0

2 years ago

The function s(t) represents the position of an object at time t moving along a line. Suppose s (2 )equals 146and s (6 )equals

sineoko [7]

Answer:

v(t) = 27 units

Explanation:

The function s(t) represents the position of an object at time t moving along a line such that,

$s(2)=146$

and

$s(6)=254$

We need to find the average velocity of the object over the interval of time [2,6]. The velocity of the object is equal to the total distance divided by time. It is given by :

$v(t)=\dfrac{s(6)-s(2)}{6-2}$

$v(t)=\dfrac{254-146}{6-2}$

v(t) = 27 units

So, the average velocity of the object is 27 units. Hence, this is the required solution.

5 0

3 years ago

Which three types of electromagnetic waves carry most of the Sun's energy that strikes Earth?

pshichka [43]

Answer:

Explanation:

3 0

4 years ago