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3 years ago

I need it now aaaasssssaaaappp!!!!

Physics

1 answer:

Vera_Pavlovna [14]3 years ago

5 0

A) Pitch depends on the frequency of a sound wave. The higher the pitch, the higher the frequency and the lower the pitch, the lower the frequency. Sound waves have different pitches due to varying frequency levels.

B) Sound is created as the pen vibrates. This vibrations also interacts with the air atoms and molecules, causing them to vibrate too, therefore, creating sound waves. The reason the brain grows annoyed at this continual sound is because the brain will focus on this sound only, causing the brain to go into overdrive, creating annoyance.

C) Sound waves are travelling vibrations of particles. Space does not have any atoms or particles for the sound vibrations to interact with, therefore creating zero sound waves to travel.

Hope this helps!! :))

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A 1.50 V potential difference is maintained across a 1.50 m wire that has a cross-sectional area of 0.600 mm2. How much power is

Goshia [24]

Given that the potential difference is V = 1.5 V.

The length of the wire is l = 1.5 m.

The cross-sectional area is

$\begin{gathered} A\text{ = 0.6 }mm^2 \\ =0.6\times10^{-6}m^2 \end{gathered}$

The resistivity of the wire is

$\rho\text{ = 5.25}\times10^{-8}\Omega\text{ m }$

We have to find the power dissipated in the wire.

First, we need to calculate resistance.

The resistance can be calculated as

$\begin{gathered} R\text{ = }\rho\frac{l}{A} \\ =5.25\times10^{-8}\times\frac{1.5}{0.6\times10^{-6}} \\ =0.13125\Omega \end{gathered}$

The formula to calculate power is

$P\text{ =}\frac{V^2}{R}$

Substituting the values, the power will be

$\begin{gathered} P\text{ = }\frac{(1.5)^2}{0.13125} \\ =17.1\text{ W} \end{gathered}$

Thus, the power dissipated in the wire is 17.1 W

5 0

2 years ago

Plzzzz help 50 points thanks Super easy I will mark brainlest

Vladimir79 [104]

Yeah, which one of the three

8 0

3 years ago

how do you solve this problem. A bat flying at 3.7m/s spots an insect 23.8 meters away. How much must the bat increase its speed

RideAnS [48]

Here's how I would do it:

How far does he have to go to catch the bug ? 23.8 meters

How soon does he want to get there ? 1.8 seconds

What speed does he need ? (23.8 m) / (1.8 sec) = 13.222 m/sec

What speed is he flying now? 3.7m/s

How much does he need to increase it ? (13.222 - 3.7) = 9.5 m/s faster

5 0

3 years ago

A football quarterback throws a football for a long pass. While in the motion of throwing, the quarterback moves the ball , star

sergejj [24]

This question is incomplete, the complete question is;

A football quarterback throws a 0.408 kg football for a long pass. While in the motion of throwing, the quarterback moves the ball 1.909 m, starting from rest, and completes the motion in 0.439 s. Assuming the acceleration is constant, what force does the quarterback apply to the ball during the pass ;

a) F_throw = 8.083 N

b) F_throw = 9.181 N

c) F_throw = 2.284 N

d) F_throw = 16.014 N

e) None of these is correct

Answer:

the quarterback applied a force of 8.083 N to the ball during the pass

so Option a) F_throw = 8.083 N is the correct answer

Explanation:

Given that;

m = 0.408 kg

d = 1.909 m

u = 0 { from rest}

t = 0.439 s

Now using Kinetic equation

d = ut + 1/2 at²

we substitute

1.909 = (0 × 0.439) + 1/2 a(0.439)²

1.909 = 0 + 0.09636a

1.909 = 0.09636a

a = 1.909 / 0.09636

a = 19.8111 m/s²

Now force applied will be;

F = ma

we substitute

F = 0.408 × 19.8111

F = 8.0828 ≈ 8.083 N

Therefore the quarterback applied a force of 8.083 N to the ball during the pass

so Option a) F_throw = 8.083 N is the correct answer

5 0

3 years ago

What are the differences between forces and pressure

slamgirl [31]

Answer:

Force is a push or pull action between objects. Pressure is force acting on a surface area of an object, thus it is force per unit area.

Explanation:

4 0

3 years ago