All categories

3 years ago

What would happen if the louisiana purchase did not double the United States?

Physics

1 answer:

maks197457 [2]3 years ago

3 0

Answer:

The Louisiana Purchase eventually doubled the size of the United States, greatly strengthened the country materially and strategically, provided a powerful impetus to westward expansion, and confirmed the doctrine of implied powers of the federal Constitution.

You might be interested in

A baseball with a mass of 0.3kg is thrown into the air with a speed of 50 m/s and is at a height of 10m above. What is the speed

makkiz [27]

a una velocidad de

22 m/s, quien lo golpea y devuelve en la misma

dirección con una velocidad de 14 m/s. Si el

tiempo de contacto del balón con la jugadora es

de 0,03 s, ¿con qué fuerza golpeó la jugadora el

balón?

21 Una bala de 0,8 g, está en la recámara de un rifl e

cuando se g

6 0

3 years ago

What happens when a boxer doesn't make weight?

ryzh [129]

They would just have to box in a higher weight class

6 0

3 years ago

You are walking down a straight path in a park and notice there is another person walking some distance ahead of you. The distan

Setler79 [48]

Answer:

25.52 m

Explanation:

Relative speed between the person and I would be the difference of our speeds

$v_r=2.85-1.09=1.76\ m/s$

Time taken by me to walk up to the person = 14.5 s

Distance is given by

$Distance=Speed\times Time\\\Rightarrow s=vt\\\Rightarrow s=1.76\times 14.5\\\Rightarrow s=25.52\ m$

The person was 25.52 m ahead of me when I started running

5 0

3 years ago

The maximum tension the wire can withstand without breaking is 300 N . A 0.800 kg projectile traveling horizontally hits and emb

topjm [15]

Answer:

Let's investigate the case where the cable breaks.

Conservation of angular momentum can be used to find the speed.

$\vec{L}_1 = \vec{L}_2\\\vec{L}_1 = m\vec{v_0} \\\vec{L}_2 = I\vec{\omega}\\$

The projectile embeds itself to the ball, so they can be treated as a combined object. <u>The moment of inertia of the combined object is equal to the sum of the moment of inertia of both objects. </u>

$I = I_{projectile} + I_{ball}\\I = mr^2 + mr^2\\I = 2mr^2$

where r is the length of the cable.

<u>After the collision, the ball and the projectile makes a circular motion because of the cable.</u> So, the force (tension) in circular motion is

$F = \frac{mv^2}{r}$

The relation between linear velocity and the angular velocity is

$v = \omega r$

So,

$F = \frac{m(\omega r)^2}{r} = m\omega^2 r = 300\\mv_0r =I\omega\\\\\omega = mv_0r/I\\300 = m(\frac{mv_0r}{I})^2r = m(\frac{mv_0r}{2mr^2})^2r = m(\frac{v_0}{2r})^2r = \frac{mv_0^2r}{4r^2} = \frac{mv_0^2}{4r}\\300 = \frac{0.8v_0^2}{4r}\\1500 = v_0^2/r\\v_0 = \sqrt{1500r}$

As can be seen, the maximum velocity for the projectile without breaking the cable is $\sqrt{1500r}$ , where r is the length of the cable.

6 0

3 years ago

A spring has a relaxed length of 26 cm (0.26 m) and its spring stiffness is 11 n/m. you glue a 69 gram block (0.069 kg) to the t

Lynna [10]

Some dogs may inherit a susceptibility to epilepsy.

3 0

3 years ago