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2 years ago

What is the pH value of Potassium hydroxide

Chemistry

2 answers:

GaryK [48]2 years ago

6 0

10-14 is the ph value of potassium hydroxide

RSB [31]2 years ago

3 0

Answer:

from 10-14

Explanation:

the pH of potassium hydroxide is extremely high and is a strong base although the exact value depends on the concentration of the base in water.

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g at constant temperature, a sample of helium at 2 atm in a closed container was compressed from 5.00 L to 3.00 L. what was the

Firdavs [7]

The new pressure exerted by helium on its container is 2533.33 torr.

Boyle's law: For a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional. so PV= constant.

At constant temperature and moles,

P1V1 = P2V2.

The original sample is at 2atm torr and volume 5.00 L and then helium gas was compressed to 3.00 L

∴ P₁V₁ = P₂V₂

(2× 760 torr)(5.00 L ) = (3.00 L )(x torr),

x = 2533.33 torr.

P₂ = 2533.33 torr.

Therefore, the new pressure exerted by helium on its container is 2533.33 torr.

Learn more about pressure here:

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3 years ago

Please help I’ll give you guys brainiest! Thank youuuuuuu :))

Nana76 [90]

Answer:

Balanced.

Explanation:

Both sides are pulling with equal force.

4 0

3 years ago

Read 2 more answers

How many electrons are in the outermost energy level of a neutral Fluorine atom?

Yuki888 [10]

Answer:

The answer is 7 (seven)

Explanation:

Fluorine has seven of eight possible electrons in its outermost energy level, which is energy level II.

5 0

3 years ago

How much volume will 8.8 moles of gas fill at 0.12 atm at 56*C

Neporo4naja [7]

Answer:

2000 L

General Formulas and Concepts:

Atomic Structure

Moles
Temperature Conversion: K = °C + 273.15

Gas Laws

Ideal Gas Law: PV = nRT

P is pressure
V is volume (in L)
n is number of moles
R is gas constant
T is temperature (in K)

Explanation:

Step 1: Define

[Given] 8.8 moles gas

[Given] 0.12 atm

[Given] 56 °C = 329.15 K

Step 2: Solve for V

Substitute in variables [Ideal Gas Law Formula]: $\displaystyle (0.12 \ atm)V = (8.8 \ mol)(0.0821 \ \frac{L \cdot atm}{mol \cdot K})(329.15 \ K)$
Isolate V: $\displaystyle V = \frac{(8.8 \ mol)(0.0821 \ \frac{L \cdot atm}{mol \cdot K})(329.15 \ K)}{(0.12 \ atm)}$
Multiply/Divide [Cancel out units]: $\displaystyle V = 1981.7 \ L$