What does geocentric mean

Chemistry

2 answers:

motikmotik3 years ago

5 0

Answer:

Relating to, measured from, or as if observed from the earth's center.

larisa86 [58]3 years ago

5 0

Having or representing the earth as the center, as in former astronomical systems

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How is energy involved in physical change?

enyata [817]

Answer:

when solid dry ice vaporizes (physical change), carbon dioxide molecules absorb energy. When liquid water becomes ice, energy is released. Remember that all chemical reactions involve a change in the bonds of the reactants.

Explanation:

3 0

3 years ago

Read 2 more answers

Compounds X, C9H19Br, and Y, C9H19Cl, undergo base-promoted E2 elimination to give the same single alkene product, Z. Catalytic

Pavlova-9 [17]

Answer:

Compound X= 4-bromo-2,3,3-trimethylhexane

Compound Y= 5-chloro-2,3,3-trimethylhexane

Explanation:

The first step is set up the problem. That way we can obtain some clues. If we check figure 1 we can obtain some ideas:

-) If we have E2 reaction is not possible a methyl or hydride shift.

-) If we have an E2 reaction we will need an H in anti position to obtain the double bond. Therefore a double bond with the quaternary carbon (the carbon bonded to the 2 methyl groups).

The second step is to solve the alkene structure. We have to put the leaving group near to carbon that has more possible removable hydrogens. That's why the double bond is put it between carbons 5 and 4 of the alkane (Figure 2).

The third step is the structure of the alkyl bromide structure. To do this we have to check the alcohol produced by the alkene. In the hydration of alkanes reaction we will have a carbocation formation. Therefore we can have for the alkene proposed a methyl shift to obtain the most stable carbocation. With this in mind, we have to do the same for the Alkyl bromide that's why the Br is put it carbon 4 of the alkane. If we put the Br on this carbon we can have the chance of this methyl shift also, to obtain the same alcohol (figure 3).

Finally, for the alkyl chloride, we only have 2 choices because to produce the alkane we have to put the leaving group on one of the 2 carbons of the double bond. If we choose the same carbon on which we put the Br we can have the same behavior of the alkyl bromide (the methyl shift), therefore we have to put in the other carbon.