Answer:
Corresponds to a covalent compound.
Explanation:
Both Boron and Fluorine are nonmetals, forming a covalent bond, the result of which is the boron trifluoride compound (BF3). This is a highly toxic gas.
It is synthesized by the reaction between hydrogen fluoride and boron oxide:
B2O3 + 6 HF → 2 BF3 + 3 H2O
I would personally convert the 12 mg to g so I could see what I was working with. So 12 mg to grams is 0.012 g...
so 1 tablet is 0.012g. the patient needs 0.024 g.
so 0.024g/0.012g = 2 tablets or 0.012g X 2 is 0.024 g
hope this helps :)
<span>the balanced equation for the reaction is as follows ;
Na</span>₂S + 2AgNO₃ ---> 2NaNO₃ + Ag₂<span>S
stoichiometry of Na</span>₂S to AgNO₃<span> is 1:2
number of AgNO</span>₃<span> moles reacted - 0.315 mol/L x 0.04000L = 0.0126 mol according to molar ratio of 1:2
number of Na</span>₂S moles required are - 1/2 x number of AgNO3 moles reacted Na₂<span>S moles = 0.0126 mol /2 = 0.00630 mol
molarity of Na</span>₂<span>S - 0.260 M
there are 0.260 mol in 1 L
therefore 0.00630 mol are in - 0.00630 mol / 0.260 mol/L
volume of Na</span>₂<span>S required = 0.0242 L
volume of Na</span>₂S required = 24.4 mL