Answer:
HCl < CH₃COOH < NH₃ < NaOH
Explanation:
Given compounds:
Acetic acid: CH₃COOH
Ammonia; NH₃
Hydrochloric acid: HCl
Sodium hydroxide: NaOH
All the solutions are of the same molarity which is 0.1M. We need to see how these compounds dissociate to form solutions in order to establish their pH value:
For Acetic acid;
CH₃COOH + H₂O ⇄ H₃O⁺ + CH₃COO⁻
Acetic acid is a weak acid and it ionizes slightly in solutions. It would have a pH close to 7
For Ammonia;
NH₃ + H₂O ⇄ NH₄⁺ + OH⁻
Ammonia is a weak base and it ionizes slightly in solutions. It sets up an equilibrium in the process. It's would be slightly above 7
For HCl:
HCl + H₂O → H₃O⁺ + Cl⁻
HCl is a strong acid and ionizes completely in solutions. It has a very low pH
For NaOH:
NaOH → Na⁺ + OH⁻
NaOH ionizes also completely in solutions and it breaks down into sodium and hydroxide ions. It is a strong base and it would have a high PH value.
HCl < CH₃COOH < NH₃ < NaOH
This is the trend of increasing pH
Answer:
<em>the speed at which a chemical reaction proceeds.</em>
So the solution inside doesn't splash
(a) The displacement of point P at time t=0.10s is determined as +2cm.
(b) The displacement of point P at time t=0.20s is determined as -2cm.
<h3>
What is displacement?</h3>
Displacement is the change in position of an object. It is obtained from the product of velocity and time of motion.
x = vt
<h3>Displacement of the waves after 0.1 s</h3>
x = 10 m/s x 0.1 s = 1 m
Each wave will travel 1 m to the right or to the left, depending on the initial direction.
- wave B from left will stop at point 0 m
- wave A from left will stop at point -1 m
- wave C from right will stop at point 0 m
- wave D from right will stop at point + 1 m
wave B and C superimposed and the displacement will be between A and D.
Amplitude of A = - 2cm
Amplitude of D = + 4cm
Displacement of point P = 4 cm - 2 cm = 2cm
<h3>Displacement of the waves after 0.2 s</h3>
x = 10 m/s x 0.1 s = 2 m
Each wave will travel 2 m to the right or to the left, depending on the initial direction.
- wave B from left will stop at point 1 m
- wave A from left will stop at point 0 m
- wave C from right will stop at point -1 m
- wave D from right will stop at point 0 m
Displacement of point P = (amplitude B + amplitude C) + (amplitude A + amplitude D)
Displacement of point P= (2cm - 2cm) + (2 cm - 4cm)= -2cm
Learn more about displacement here: brainly.com/question/2109763
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