What’s the balanced equation of sodium hydroxide + carbon dioxide produces sodium carbonate + water?

Which type of reaction occurs in the following equation?

Tems11 [23]

The type of reaction in above reaction is refered to as a disproportionation reaction .It sometimes used to describe desymmetrizing reaction.in the equation above compounds of intermediate oxidation state are converted to two different compound, that is Clo3 ions and 2cl-

3 0

3 years ago

3.00 moles of nitrogen and 4.00 moles of oxygen are placed in a 35.0 L container at a temperature of 298 K. What is the pressure

Leto [7]

Answer:

i think the answer is c hoped this helped

Explanation:

7 0

2 years ago

the average speeds of gas molecules in.cylinders A,b,c,d are 0.01 m/s, 0.005m/s ,0.1 m/s and 0.5 m/s, respectively .which cylind

Darya [45]

<span>The average speed of the gas is related to the kinetic energy of the gas. The kinetic energy of the gas is also related to the temperature of the gas. If the average speed of the gas is closer to zero, it means that it has very low motion or kinetic energy. This can be inferred that the gas has a very low temperature. At absolute zero, the motion of all the gas molecules stops. This means that the kinetic energy of the gas is also zero. Zero kinetic energy means zero average speed.</span> <span>So, the answer is cylinder B. The average speed of the gas in cylinder B is closest to zero.</span>

8 0

3 years ago

What is the % composition of Carbon in Chromium (iii) Carbonate

photoshop1234 [79]

Step 1 - Discovering the ionic formula of Chromium (III) Carbonate

Chromium (III) Carbonate is formed by the ionic bonding between Chromium (III) (Cr(3+)) and Carbonate (CO3(2-)):

$Cr^{3+}+CO^{2-}_3\rightarrow Cr_2(CO_3)_3$

Step 2 - Finding the molar mass of the substance

To find the molar mass, we need to multiply the molar mass of each element by the number of times it appears in the formula of the substance and, finally, sum it all up.

The molar masses are 12 g/mol for C; 16 g/mol for O and 52 g/mol for Cr. We have thus:

$\begin{gathered} C\rightarrow3\times12=36 \\ \\ O\rightarrow9\times16=144 \\ \\ Cr\rightarrow2\times52=104 \end{gathered}$

The molar mass will be thus:

$M=36+104+144=284\text{ g/mol}$

Step 3 - Finding the percent composition of carbon

As we saw in the previous step, the molar mass of Cr2(CO3)3 is 284 g/mol. From this molar mass, 36 g/mol come from C. We can set the following proportion:

$\begin{gathered} 284\text{ g/mol ---- 100\%} \\ 36\text{ g/mol ----- x} \\ \\ x=\frac{36\times100}{284}=\frac{3600}{284}=12.7\text{ \%} \end{gathered}$

The percent composition of Carbon is thus 12.7 %.

8 0

1 year ago

sulfate = SO4 -2 phosphate = PO4 -3 hydroxide = OH- sodium hydroxide aNa(OH)2 bNa(OH)3 cNa2OH 4NaOH

blsea [12.9K]

4. NaOH
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6 0

3 years ago