Answer is: volume of H₂SO₄ is 42.1 mL.<span>
Chemical reaction: H</span>₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.<span>
c(H</span>₂SO₄) = 0,4567 M = 0,4567 mol/L.<span>
V(NaOH) = 30 mL </span>÷ 1000 mL/L <span>= 0,03 L.
c(NaOH) = 0,321 M = 0,321 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,321 mol/L · 0,030 L.
n(NaOH) = 0,00963 mol.
From chemical reaction: n(H</span>₂SO₄) : n(NaOH) = 1 : 2.<span>
n(H</span>₂SO₄) = 0,01926 mol.<span>
V(H</span>₂SO₄) = n(H₂SO₄) ÷ c(H₂SO₄).<span>
V(H</span>₂SO₄) = 0,01926 mol ÷ 0,4567 mol/L.<span>
V(H</span>₂SO₄<span>) = 0,0421 L = 42,1 mL.</span>
A mountain system is a geographic area containing numerous geologically realted mountains.
Answer:
46.0g of Iron are produced
Explanation:
Based on the chemical reaction:
FeO(l) + Mg(l) → Fe(l) + MgO(s)
<em>1 mole of Iron (II) oxide reacts per mole of Mg to produce 1 mole of iron</em>
<em />
To solve this question we need to convert each mass of reactant to moles using its respectives molar masses in order to find limitng reactant. Moles of limiting reactant = Moles of iron produced:
<em>Moles FeO (Molar mass: 71.85g/mol):</em>
80.0g * (1mol / 71.85g) = 1.11moles FeO
<em>Moles Mg (Molar mass: 24.305g/mol)</em>
20.0g * (1mol / 24.305g) = 0.823 moles Mg
As moles of Mg < Moles FeO, Mg is limiting reactant and the moles of Fe are 0.823 moles.
The mass of Iron produced is:
0.823 moles Fe * (55.845g/mol) =
46.0g of Iron are produced
