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gayaneshka [121]
2 years ago
8

3. 2KOH + H2SO4 = K2SO4 + 2H2O what chemical reaction is it.

Chemistry
1 answer:
Serjik [45]2 years ago
5 0
From what is given, double replacement is what it is
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having that coloration is selected for since many predators will recognize it and stay away. Therefore the common coloration is
garri49 [273]

Answer: Natural selection.

Explanation:

The natural selection is the process by which the organism that best suits the characters will survive and the organism which cannot adapt the changes will die.

The predators feed on their prey and the organism which hides easily in the environment due to its color is safe and the animals that cannot camouflage will die.

This is natural selection that more favored character is carried out over generations and other that cannot survive die.

5 0
4 years ago
What are the coefficients to balance the following equation?<br> ba+br=babr2
scoray [572]
1 ba+2 br——>1 babr2

u just have to make sure u have the same number of each type of atom on either side of the equation:)
8 0
3 years ago
HELP ASAP
WARRIOR [948]
The snake,raccoon, and preying mantis
4 0
3 years ago
Titration of 0.824 g of potassium hydrogen phthalate required 38.314 g of naoh solution to reach the end point detected by pheno
melamori03 [73]

1.062 mol/kg.

<em>Step 1</em>. Write the balanced equation for the neutralization.

MM = 204.22 40.00

KHC8H4O4 + NaOH → KNaC8H4O4 + H2O

<em>Step 2</em>. Calculate the moles of potassium hydrogen phthalate (KHP)

Moles of KHP = 824 mg KHP × (1 mmol KHP/204.22 mg KHP)

= 4.035 mmol KHP

<em>Step 3</em>. Calculate the moles of NaOH

Moles of NaOH = 4.035 mmol KHP × (1 mmol NaOH/(1 mmol KHP)

= 4.035 mmol NaOH

<em>Step 4</em>. Calculate the mass of the NaOH

Mass of NaOH = 4.035 mmol NaOH × (40.00 mg NaOH/1 mmol NaOH)

= 161 mg NaOH

<em>Step 5</em>. Calculate the mass of the water

Mass of water = mass of solution – mass of NaOH = 38.134 g - 0.161 g

= 37.973 g

<em>Step 6</em>. Calculate the molal concentration of the NaOH

<em>b</em> = moles of NaOH/kg of water = 0.040 35 mol/0.037 973 kg = 1.062 mol/kg

3 0
4 years ago
Cesium has a radius of 272 pm and crystallizes in a body-centered cubic structure. What is the edge length of the unit cell
olchik [2.2K]

Answer: Edge length of the unit cell = 628pm

Explanation: For a body centred cubic structured system, the relationship between the edge length of the unit cell and radius of the atoms in the structure is

Edge length of Unit cell (a) = (4R)/(√3)

R = 272pm = (272 × (10^-12))m = (2.72 × (10^-10))m

a = (4 × (2.72 × (10^-10)))/(√3)

a = (6.28157 × (10^-10))m = 628pm

4 0
3 years ago
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