Answer: Compounds that contain a carbon-carbon double bond are known as _____alkenes_______ . Alkenes are electron rich; therefore, simple alkenes do not react with _____nuceophiles_______ or bases, but will react with _____electrophiles_______ or acids. In the IUPAC system, an alkene is identified by the suffix _____-ene_______ . Addition reactions in which two parts of a reagent are added to the same side of a double bond are known as _____syn_______ additions. Addition reactions in which two parts of a reagent are added from opposite sides of a double bond are called _____anti_______ additions. Halogenation and halohydrin formation occur with _____anti_______ addition. Hydroboration occurs with _____syn_______ addition.
Explanation:
The right terms have been filled into the statement.
Electrophiles are election rich so they react with nucleophiles. And vice versa.
Addition reactions in which two parts of a reagent are added to the same side of a double bond are known as _syn reaction and that involving opposite is anti reaction.
The Halohydrin formation reaction involves breaking a pi bond and creating a halohydrin in its place. Halo = halogen and Hydrin = OH. This reaction takes place in water and yields an anti-addition reaction which follows Markovnikov's rule.
Answer:
Molar ratio of the compound is 1:1 and the type of hydrate is Mono hydrate.
Explanation:
From the given,
Mass of sodium carbonate 
= 8.85 g
Loss mass 
= 1.28 g
Actual weight of sodium carbonate = 8.85 g - 1.28 g = 7.57 g
Therefore, the compound has only one water molecule.
Molecular formula of the compound is 
an name of the compound is <u>sodium carbonate mono hydrate.</u>
Hence, the type of the compound is Mono hydrate.
So they can predict what happens next
Answer: mg(OH)2 = +37
Rbl = 31
RbOH= -83
mgl2= -144
Explanation: just did it on edge2020
