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Harlamova29_29 [7]
3 years ago
7

List two situations in which measurements have unlimited number of significant figures

Chemistry
1 answer:
GaryK [48]3 years ago
5 0
Your answers would be, (Ex. 3*3*3*3....etc..).
(1), When measurements involving counting
(2), When measurement involves exactly defined quantities




Hope that helps!!!

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Alkali metals
Evgen [1.6K]
The answer is going to be A.
3 0
3 years ago
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0.28gram of NH3 on decomposition gave 0.25gram of nitrogen and hydrogen. Find the volume of hydrogen evolved at Ntp. (2gram hydr
hodyreva [135]

The volume of H₂ evolved at NTP=0.336 L

<h3>Further explanation</h3>

Reaction

Decomposition of NH₃

2NH₃ ⇒ N₂ + 3H₂

conservation mass : mass reactants=mass product

0.28 NH₃= 0.25 N₂ + 0.03 H₂

2 g H₂ = 22.4 L

so for 0.03 g :

\tt \dfrac{0.03}{2}\times 22.4=0.336

7 0
3 years ago
Show all calculations. 1. 2 C 4 H 10 + 13 O 2 -&gt; 8 CO 2 + 10 H 2 O a) what mass of O 2 will react with 400 g C 4 H 10? b) how
bazaltina [42]

\\ \tt\hookrightarrow 2C_4H_10+13O_2\longrightarrow 8CO_2+10H_2O

  • 13mol of O_2 reacts with 2mols of C_4H_10.
  • 7.5mol of O_2 reacts with 1mol of C_4H_10

No of moles:-

\\ \tt\hookrightarrow \dfrac{Given\:mass}{Molar\:mass}

\\ \tt\hookrightarrow \dfrac{400}{58}

\\ \tt\hookrightarrow 6.89mol

Now

Moles of O_2

\\ \tt\hookrightarrow 7.5(6.89)=51.6mol

Mass of O_2

\\ \tt\hookrightarrow 51.6(32)=1651.2g

4 0
2 years ago
Cu2 -&gt; Cu2+ is it getting oxidized?
KIM [24]

Answer:

Explanation:

Cu²⁺ + 2e⁻  →  Cu   ( copper gets reduced )

Cu  → Cu²⁺ + 2e⁻ (  copper gets oxidized )

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Consider the following reactions.

4KI + 2CuCl₂  →   2CuI  + I₂  + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced.

CO + H₂O   →  CO₂ + H₂

the oxidation state of carbon is +2 on reactant  side and on product side it becomes  +4 so carbon get oxidized.

Na₂CO₃ + H₃PO₄  →  Na₂HPO₄ + CO₂ + H₂O

The oxidation state of carbon on reactant side is +4. while on product side is  also +4 so it neither oxidized nor reduced.

H₂S + 2NaOH → Na₂S + 2H₂O

The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.

7 0
3 years ago
What is the oxidation number of chlorine
sergiy2304 [10]
The oxidation number of chlorine in the Cl-<span> ion is -1.</span>
3 0
3 years ago
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