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2 years ago

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The sum of two prime numbers is 85. What is the product of these two prime numbers?

1 answer:

hodyreva [135]2 years ago

6 0

Observe that 85 is an odd number. That means, one of the prime numbers must be even to have an odd sum with another odd number. As we know, the only even prime number is 2. Hence, the other number is 83. So, the product of these two prime numbers is 83 x 2 = 166. Thus, the answer is 166<span>. </span>

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What are the coordinates of the point on the directed line segment from (1,-5) to

Black_prince [1.1K]

Answer:

Q (2.5, -4)

Step-by-step explanation:

Let A (1, -5), C = (10, 1), find Q (x, y), so that AQ:QC = 1:5

AQ = (x - 1, y + 5)

QC = (10 - x, 1 - y)

AQ:QC = 1:5

so 5*AQ = QC

5(x - 1) = (10 - x)

5(y + 5) = 1 - y

Solve them:

5x - 5 = 10 - x

6x = 15

x = 15/6 = 2.5

5y + 25 = 1 - y

6y = -24

y = -24/6 = -4

Then answer is Q (2.5, -4)

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2 years ago

Identify the zeros of the polynomial function N(x)=1/2 (x-1)(x+3).

zhannawk [14.2K]

Answer:

a:x=-3

c:x=1

Step-by-step explanation:

The zeros of a function are the values of x for which the value of the function f(x) becomes zero.

In this problem, we have the following function:

$f(x)=\frac{1}{2}(x-1)(x+3)$

Here we want to find the zeros of the function, i.e. the values of x for which

$f(x)=0$

In order to make f(x) equal to zero, either one of the factors $(x-1)$ or $(x+3)$ must be equal to zero.

Therefore, the two zeros can be found by requiring that:

1)

$x-1=0\\\rightarrow x=+1$

2)

$x+3=0\\\rightarrow x=-3$

So the correct options are

a:x=-3

c:x=1

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