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Degger [83]
2 years ago
12

use the fact that there are 2pi radians in each circle to find another angle, smaller than 2pi, that is equivalent to 17pi/6. wi

th detailed steps pleasee
Mathematics
1 answer:
Gekata [30.6K]2 years ago
3 0

The equivalent angle in the interval [0, 2pi] is 5pi/6.

<h3>How to find the equivalent angle?</h3>

Remember that for any given angle θ in radians, we define a family coterminal or equivalent angles as:

A = θ + n*(2pi)

Where n is a whole number.

Now we want to find an angle equivalent to 17pi/6 that is on the range between 0 and 2pi.

Then we can write:

A = 17pi/6 + n*(2pi)

If we use n = -1, then we get:

A = 17pi/6 - 2pi = 17pi/6 - 12pi/6 = 5pi/6

This is the equivalent angle in the desired range.

If you want to learn more about equivalent angles:

brainly.com/question/24839702

#SPJ1

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Two point particles are attached to each other via a light in-extensible string that passes over a ring hanging from the ceiling
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a. The expression for the tension in the string is T = mg

b. The expression for the tension in the chain is T = 2mg

To solve the problem, we need to know what tension is.

<h3>What is tension?</h3>

This is the opposing force in a stretched material.

<h3>a. Tension in the string</h3>

The expression for the tension in the string is T = mg

Since the string supports the weight of the object, the tension in the string equals the weight of the particle.

Let

  • T = tension in sring and
  • W = weight of particle = mg where
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  • g = acceleration due to gravity

So, T = W

T = mg

So, the expression for the tension in the string is T = mg

<h3>b. Tension in chain</h3>

The expression for the tension in the chain is T = 2mg

<h3 />

Since the chain supports both strings, the tension in the chain equals the tension in both strings.

Let

  • T' = tension in chain and
  • T = tension in each string

So, T' = T + T

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So, the expression for the tension in the chain is T = 2mg

<h3 />

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