Answer:
a_x(3.98) = 7.0844 m/s^2
Explanation:
Given:
- The eastward component of car's velocity is given as follows:
v_x (t) = 0.890*t^2
For, 0 s < t < 5 s
Find:
What is the acceleration of the car when v_x = 14.1 m/s ?
Solution:
- We will first compute the time t at which the velocity v_x component equals 14.1 m /s :
14.1 = 0.890*t^2
t = sqrt (15.8427)
t = 3.98 s
- Now use the relation of v_x and derivative to obtain a_x acceleration in eastward direction:
a_x (t) = dv_x / dt
a_x(t) = 1.78*t
- Evaluate at t = 3.98 s:
a_x(3.98) = 1.783.98
a_x(3.98) = 7.0844 m/s^2
The height of a wave or the amount of air the wave carries is the amplitude air
Air is the word
Hope I helped
Answer:
1) Total internal reflection
2) Snell's law
Explanation:
As already mentioned in the question, on way of determining the refractive index is to use the idea of total internal reflection. In that case, we measure the critical angle. This is than angle of incidence in the material, for which the angle of refraction is 90°.
n=1/sinC
Alternatively, we could use Snell's law. In this case, we measure the angles of incidence and refraction.
Refractive index= sini/sinr
Answer:
The elastic potential energy of the spring is 0.28 J
Explanation:
Given;
mass of the block, m = 0.05 kg
spring constant, k = 350 N/m
extension of the spring, x = 4 cm = 0.04 m
The elastic potential energy of the spring is calculated as;
Therefore, the elastic potential energy of the spring is 0.28 J