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jolli1 [7]
3 years ago
7

When driving at night with other traffic, you should not look directly at oncoming headlights. Instead?

Physics
2 answers:
Arada [10]3 years ago
6 0

When driving at night with other traffic, you should not look directly at oncoming headlights. Instead look toward the right edge of your lane

<h3>Further explanation </h3>

To drive at night, make sure your headlights are on. Because if its on we can see it clearly and other drivers can see you. Also when driving at night, its recommended to drive slower than you would during the daytime becuse it takes longer to see potential hazards on the road. If you feel yourself getting drowsy, pull over at a rest stop then try to get some sleep.

If an approaching car is using its high-beams, don't look directly into the oncoming headlights, instead look towards the right edge of your lane. Watch the oncoming car out of the corner of your eye. Do not try to retaliate against the other driver by keeping your high-beam lights on. If you do, both of you can be blinded. There are no permanent eye damage from looking at car headlights, but by looking directly at any light will cause discomfort and hinder vision temporarily.

<h3>Learn more</h3>
  1. Learn more about driving at night brainly.com/question/4637543
  2. Learn more about traffic brainly.com/question/11606596
  3. Learn more about oncoming headlights brainly.com/question/12961845

<h3>Answer details</h3>

Grade:  9

Subject:  physics

Chapter:  traffic

Keywords: oncoming headlights, traffic, driving at night, look, driving

12345 [234]3 years ago
5 0
<span>
watch the right edge of your lane and check the position of oncoming cars. </span>
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Which of the following can explains convection?
Vikentia [17]

Answer:

A) would be the best explanation because hot air is less dense and would rise to the top of a column of air

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2 years ago
PLEASE HELP!!!!!!
SashulF [63]


Somewhere in your book or your notes, you must have met the formula for the
gravitational attraction between two bodies.  If you can go back and find it, you
only need to plug your numbers into that formula, and out will pop the answer.

Formula:                            <u>Force = G (mA x mB) / (distance)²</u>

If everything is in SI units, then        G = 6.67 x10⁻¹¹ newton-meter² / kilogram²

You said that
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7 0
3 years ago
A 45.0 kg girl is standing on a 159 kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat,
Ganezh [65]

Answer:

(a) v_g_i=1.08\frac{m}{s}

(b) v_p_i=-0.3\frac{m}{s}

Explanation:

According to the law of conservation of momentum:

\Delta p=0\\p_i=p_f

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0=m_gv_g_i+m_pv_p_i\\v_p_i=-\frac{m_gv_g_i}{m_p_i}(1)

(a) The velocity of the girl relative to the ice is:

v_g_i=v_g_p+v_p_i(2)

Here, v_g_p is the velocity of the girl relative to the plank and v_p_i is the velocity of the plank relative to the ice.

Replacing (1) in (2):

v_g_i=v_g_p-\frac{m_gv_g_i}{m_p_i}\\v_g_i+\frac{m_gv_g_i}{m_p_i}=v_g_p\\v_g_i(1+\frac{m_g}{m_p})=v_g_p\\v_g_i=\frac{v_g_p}{1+\frac{m_g}{m_p}}\\v_g_i=\frac{1.38\frac{m}{s}}{1+\frac{45kg}{159kg}}\\v_g_i=1.08\frac{m}{s}

(b) According to (2), the velocity of the plank relative to the surface of ice is:

v_p_i=v_g_i-v_g_p\\v_p_i=1.08\frac{m}{s}-1.38\frac{m}{s}\\v_p_i=-0.3\frac{m}{s}

The negative sing indicates that the plank is moving to the left.

3 0
3 years ago
What type of wave would a vibrating bell make?
Softa [21]
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Nookie1986 [14]

Answer:

C ) 33 s.

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4 0
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