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jolli1 [7]
3 years ago
7

When driving at night with other traffic, you should not look directly at oncoming headlights. Instead?

Physics
2 answers:
Arada [10]3 years ago
6 0

When driving at night with other traffic, you should not look directly at oncoming headlights. Instead look toward the right edge of your lane

<h3>Further explanation </h3>

To drive at night, make sure your headlights are on. Because if its on we can see it clearly and other drivers can see you. Also when driving at night, its recommended to drive slower than you would during the daytime becuse it takes longer to see potential hazards on the road. If you feel yourself getting drowsy, pull over at a rest stop then try to get some sleep.

If an approaching car is using its high-beams, don't look directly into the oncoming headlights, instead look towards the right edge of your lane. Watch the oncoming car out of the corner of your eye. Do not try to retaliate against the other driver by keeping your high-beam lights on. If you do, both of you can be blinded. There are no permanent eye damage from looking at car headlights, but by looking directly at any light will cause discomfort and hinder vision temporarily.

<h3>Learn more</h3>
  1. Learn more about driving at night brainly.com/question/4637543
  2. Learn more about traffic brainly.com/question/11606596
  3. Learn more about oncoming headlights brainly.com/question/12961845

<h3>Answer details</h3>

Grade:  9

Subject:  physics

Chapter:  traffic

Keywords: oncoming headlights, traffic, driving at night, look, driving

12345 [234]3 years ago
5 0
<span>
watch the right edge of your lane and check the position of oncoming cars. </span>
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A 2.4-kg ball falling vertically hits the floor with a speed of 2.5 m/s and rebounds with a speed of 1.5 m/s. What is the magnit
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9.6 Ns

Explanation:

Note: From newton's second law of motion,

Impulse = change in momentum

I = m(v-u).................. Equation 1

Where I = impulse, m = mass of the ball, v = final velocity, u = initial velocity.

Given: m = 2.4 kg, v = 2.5 m/s, u = -1.5 m/s (rebounds)

Substitute into equation 1

I = 2.4[2.5-(-1.5)]

I = 2.4(2.5+1.5)

I = 2.4(4)

I = 9.6 Ns

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3 years ago
8a. What is the equivalent resistance of the following circuit?
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Answer: Take your pick

Explanation:

if they are all in parallel 1 /(1/100 + 1/300 + 1/50) = 30 Ω

if 50 is in parallel with 2 in series 1 / (1/(100 + 300) + 1/50) = 44.444...Ω

if 100 is in parallel with 2 in series 1 / (1/(50 + 300) + 1/100) = 77.777...Ω

if 300 is in parallel with 2 in series 1 / (1/(100 + 50) + 1/300) = 100 Ω

If 50 is in series with 2 in parallel 50 + 1/(1/100 + 1/300) = 125 Ω

If 100 is in series with 2 in parallel 100 + 1/(1/50 + 1/300) = 142.857...Ω

If 300 is in series with 2 in parallel 300 + 1/(1/50 + 1/100) = 333.333...Ω

If they are all in series 100 + 300 + 50 = 450 Ω

4 0
2 years ago
The thymus gland plays an important role in the developing immune system of a child. It makes infection-fighting lymphocytes cal
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3 years ago
The energy of a given wave in the electromagnetic spectrum is 2.64 × 10-21 joules, and the value of Planck’s constant is 6.6 × 1
bixtya [17]
We are given
E = <span>2.64 × 10-21 J
h = </span><span>6.6 × 10-34 J s

The options given below are frequencies, therefore, the question must be asking about the frequency fo the given wave

The equation is
E = h f
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6 0
3 years ago
CONFUSED!!!
otez555 [7]

A. Impulse is simply the product of Force and time. Therefore,

I = F * t                                 ---> 1

where I is impulse, F is force, t is time

 

However another formula for solving impulse is:

I = m vf – m vi                    ---> 2

where m is mass, vf is final velocity and vi is initial velocity

 

Therefore using equation 2 to solve for impulse I:

I = 2000kg (0) – 2000kg (77 m/s)
I = -154,000 kg m/s

 

B. By conservation of momentum, we also know that Impulse is conserved. That means that increasing the time by a factor of 3 would still result in an impuse of -154,000 kg m/s. So,

I = F’ * (3 t) = -154,000 kg m/s

Since t is multiplied by 3, therefore this only means that Force is decreased by a factor of 3 to keep the impulse constant, therefore:

(F/3) (3t) = -154,000 kg m/s

 

 

Summary of Answers:

A. I = -154,000 kg m/s

B. Force is decreased by factor of 3

8 0
3 years ago
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