The cutoff frequency for magnesium is 8.93 x 10¹⁴ Hz.
<h3>What is cutoff frequency?</h3>
The work function is related to the frequency as
W0 = h x fo
where, fo = cutoff frequency and h is the Planck's constant
Given is the work function for magnesium is 3.70 eV.
fo = 3.7 x 1.6 x 10⁻¹⁹ / 6.626 x 10⁻³⁴
fo = 8.93 x 10¹⁴ Hz.
Thus, the cut off frequency is 8.93 x 10¹⁴ Hz.
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Answer:
confounding cause they had exposure to many programmes
Answer:
F = M a where M is acceleration and a is acceleration
a = x / s^2 = distance / time squared
The Newton is derived because mass, distance, and time are all fundamental units One would have to look at the fundamental requirements for these definitions, but they can all be repeated in a laboratory.
So the Newton is determined from these fundamental units and since the Joule equals Newton * Distance it is also derived from the fundamental units.
If one has the three fundamental units then one can derive the Joule and Newton.
Work is done. work=forcexdisplacement. the ice skater glides 2 meters (displacement), so yes.
