Answer:
나쁜 소식 원인 나는 ques 원인 메신저 한국어 내가 캔트 unfmder 대답 할 수 없습니
The answer to this is C could i please get the brainliest answer
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The radius of the sphere is r=5.15 cm=0.0515 m, and its surface is given by

So the total charge on the surface of the sphere is, using the charge density

:

The electrostatic force between the sphere and the point charge is:

where
ke is the Coulomb's constant
Q is the charge on the sphere

is the point charge
r is their separation
Re-arranging the equation, we can find the separation between the sphere and the point charge:
Given that,
Puck slide total Deltax = 12m
Puck and board Mk = 0.10
Find the initial speed = ?
We know that,
Vf^2-Vi^2 = 2a Deltax
-Vi^2 = -2MkgDeltax ............(1)
then,
fk = -Mk mg = ma
a = -Mkg .........(2)
From equation (1),
Vi^2 = 2MkgDeltax
Vi = âš2MkgDeltax [g=9.8m/s^2]
Vi = âš2(0.10)(0.98)(12)
Vi = âš0.2(9.8)(12)
Vi = âš1.92(12)
Vi = âš23.52
Vi = 4.8 m/s
Therefore the initial speed of the puck Vi = 4.8 m/s