Question

You are holding a positive charge and there are positive charges of equal magnitude 1 m to your north and 1 m to your east. what is the direction of the force on the charge you are holding?chegg

Answer 1

By holding a positive charge and there are positive charges of equal magnitude 1 m to your north and 1 m to your east. Therefore, the direction of the force on the charge you are holding will be to the southwest.

Let I hold the charge , q at the centre of given co-ordinate system and two positive charge of equal magnitude Q are placed 1 m to my North and 1 m to my South .

now, both the charge are same nature e.g., positive . Let my charge is also positive (well, you can assume negative too , I am considering positive because it makes me easy to solve) then, both charge repel to my charge.

charge Q placed on east is repelling my charge q toward west . similarly charge Q placed on North is repelling my charge q toward south.

Now , use vector for solve it.

vector $F_{net}$ = vector Fe + vector Fn,

⇒ |$F_{net}$| = $\sqrt{} F^{2} _{e } + F^{2}_n$

⇒ Fe = Fs = KqQ/(1m)² = KqQ

⇒ $F_{net}$ = √{Fe² + Fs²} = √{(kqQ)²+(KqQ)²}

⇒ $F_{net}$= √2KqQ

Hence, net force act on q {my charge } is √2KqQ and the direction of force is S - W (southwest )direction.

To learn more about positive charges here

brainly.com/question/2903220

#SPJ4