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s2008m [1.1K]
2 years ago
5

Chlorine + sulfur dioxide + water = hydrochloric acid + sulfuric acid​

Chemistry
1 answer:
scZoUnD [109]2 years ago
7 0

The given example is a chemical reaction.

The contents (separated as reactants and products) :

\begin{tabular}{c | l}Reactants & Products \\\cline{1-2}Chlorine & Sulfuric Acid \\Water & Hydrochloric Acid \\Sulfur Dioxide & \\\end{tabular}

The written reaction is :

\boxed {Cl + SO_{2} + H_{2}O \implies HCl + H_{2}SO{4}}

<em>I hope it helped you solve the problem.</em>

<em>Good luck on your studies!</em>

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You have a 1.153 g sample of an unknown solid acid, HA, dissolved in enough water to make 20.00 mL of solution. HA reacts with K
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Answer:

HA +  KOH  →  KA  +  H₂O

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The unknown solid acid in water can release its proton as this:

HA  +  H₂O  →  H₃O⁺  +  A⁻

As we have the anion A⁻, when it bonded to the cation K⁺, salt can be generated, so the reaction of HA and KOH must be a neutralization one, where you form water and a salt

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3 years ago
What mass of CaSO3 must have been present initially to produce 14.5 L of SO2 gas at a temperature of 12.5°C and a pressure of 1.
german
When the reaction equation is:

CaSO3(s) → CaO(s) + SO2(g)

we can see that the molar ratio between CaSO3 & SO2 is 1:1 so, we need to find first the moles SO2.

to get the moles of SO2 we are going to use the ideal gas equation:

PV = nRT

when P is the pressure =  1.1 atm

and V is the volume = 14.5 L 

n is the moles' number (which we need to calculate)

R ideal gas constant = 0.0821

and T is the temperature in Kelvin = 12.5 + 273 = 285.5 K

so, by substitution:

1.1 * 14.5 L = n * 0.0821 * 285.5

∴ n = 1.1 * 14.5 / (0.0821*285.5)

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so we can easily get the mass of CaSO3:

when mass = moles * molar mass

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