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2 years ago

Chlorine + sulfur dioxide + water = hydrochloric acid + sulfuric acid

Chemistry

1 answer:

scZoUnD [109]2 years ago

7 0

The given example is a chemical reaction.

The contents (separated as reactants and products) :

$\begin{tabular}{c | l}Reactants & Products \\\cline{1-2}Chlorine & Sulfuric Acid \\Water & Hydrochloric Acid \\Sulfur Dioxide & \\\end{tabular}$

The written reaction is :

$\boxed {Cl + SO_{2} + H_{2}O \implies HCl + H_{2}SO{4}}$

I hope it helped you solve the problem.

Good luck on your studies!

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At 700 K, the reaction 2SO2(g) + O2(g) <====> 2SO3(g) has the equilibrium constant Kc = 4.3 x 106. At a certain instant, f

nadya68 [22]

Answer:

The system is not in equilibrium and will evolve left to right to reach equilibrium.

Explanation:

The reaction quotient Qc is defined for a generic reaction:

aA + bB → cC + dD

$Q=\frac{[C]^{c} *[D]^{d} }{[A]^{a}*[B]^{b} }$

where the concentrations are not those of equilibrium, but other given concentrations

Chemical Equilibrium is the state in which the direct and indirect reaction have the same speed and is represented by a constant Kc, which for a generic reaction as shown above, is defined:

$Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a}*[B]^{b} }$

where the concentrations are those of equilibrium.

This constant is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients divided by the multiplication of the concentrations of the reactants also raised to their stoichiometric coefficients.

Comparing Qc with Kc allows to find out the status and evolution of the system:

If the reaction quotient is equal to the equilibrium constant, Qc = Kc, the system has reached chemical equilibrium.

If the reaction quotient is greater than the equilibrium constant, Qc> Kc, the system is not in equilibrium. In this case the direct reaction predominates and there will be more product present than what is obtained at equilibrium. Therefore, this product is used to promote the reverse reaction and reach equilibrium. The system will then evolve to the left to increase the reagent concentration.

If the reaction quotient is less than the equilibrium constant, Qc <Kc, the system is not in equilibrium. The concentration of the reagents is higher than it would be at equilibrium, so the direct reaction predominates. Thus, the system will evolve to the right to increase the concentration of products.

In this case:

$Q=\frac{[So_{3}] ^{2} }{[SO_{2} ]^{2}* [O_{2}] }$

$Q=\frac{10^{2} }{0.10^{2} *0.10}$

Q=100,000

100,000 < 4,300,000 (4.3*10⁶)

Q < Kc

The system is not in equilibrium and will evolve left to right to reach equilibrium.

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3 years ago

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3 years ago

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3 years ago

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3 years ago

1. Sulfuric acid is formed when sulfur dioxide gas reacts with oxygen gas and water. Write a balanced chemical equation for the

tekilochka [14]

Answer:

1. Balanced chemical for the given chemical reaction is :

$2SO_2(g) +O_2(g) +2H_2O(l) \rightarrow 2H_2SO_4(aq)$

number of mole of sulphuric acid produced = 12.5 mol

number of mole of oxygen required=6.25 mol

Explanation:

1. Balanced chemical for the given chemical reaction is :

$2SO_2(g) +O_2(g) +2H_2O(l) \rightarrow 2H_2SO_4(aq)$

from above balanced equation it is clearly that ,

2 mole of sulpher dioxide gives 2 mole of sulphuric acid

1 mole of sulpher dioxide gives 1 mole of sulphuric acid

therefore,

12 .5 mole of sulpher dioxide will givs 12.5 mole of sulphuric acid

number of mole of sulphuric acid produced = 12.5 mol

2 mole of sulphur dioxide needs 1 mole of oxygen gas

so,

1 mole of sulphur dioxide needs 0.5 mole of oxygen gas

therefore 12.5 of sulphur dioxide needs $12.5 \times 0.5$ mole of oxygen

number of mole of oxygen required=6.25 mol

4 0

3 years ago

Chlorine + sulfur dioxide + water = hydrochloric acid + sulfuric acid​

Chlorine + sulfur dioxide + water = hydrochloric acid + sulfuric acid