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Anna71 [15]
3 years ago
7

The pKa of a weak acid was determined by measuring the pH of a solution containing the weak acid at 0.40 M and its conjugate bas

e at 0.60 M. The measured pH was 7.8. What is the pKa of the weak acid
Chemistry
1 answer:
Alchen [17]3 years ago
8 0

Answer:

7.62

Explanation:

Given that :

pH = 7.8

Conjugate base in solution = 0.6 M

Weak Acid in solution = 0.4 M

Recall :

pH = pKa + log(conjugate base / acid)

Hence,

PKa = pH - log(conjugate base / acid)

pKa = 7.8 - log(0.6 / 0.4)

pKa = 7.8 - log(1.5)

pKa = 7.8 - 0.1760912

pKa = 7.6239088

Hence, pKa = 7.62 (2 decimal places)

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A sample of ice is heated continuously until it becomes a liquid, and then a gas. Its temperature is recorded throughout and a g
padilas [110]

Answer:

The answer to your question is: C. The specific latent heat of fusion

Explanation:

A. The specific latent heat of vaporization  Specific latent heat of vaporization indicates the transition from liquid to vapor, but we are not looking for this definition. This answer is wrong.

B. The specific heat indicates the amount of heat needed to increase the temperature of water 1°C, so this answer is wrong.

C. The specific latent heat of fusion . This heat indicate the transition from solid ie to liquid, so this is the right answer.

D. The internal energy measures the energy of the molecules of a substance, so this answer is wrong.

3 0
3 years ago
In acidic solution, the sulfate ion can be used to react with a number of metal ions. One such reaction is SO42−(aq)+Sn2+(aq)→H2
allsm [11]

Answer:

The final balanced equation is :

SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)

Explanation:

SO_4^{2-}(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+Sn^{4+}(aq)

Balancing in acidic medium:

First we will determine the oxidation and reduction reaction from the givne reaction :

Oxidation:

Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)

Balance the charge by adding 2 electrons on product side:

Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)+2e^-....[1]

Reduction :

SO_4^{2-}(aq)\rightarrow H_2SO_3(aq)

Balance O by adding water on required side:

SO_4^{2-}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)

Now, balance H by adding H^+ on the required side:

SO_4^{2-}(aq)+4H^+(aq)\rightarrow H_2SO_3(aq)+H_2O(l)

At last balance the charge by adding electrons on the side where positive charge is more:

SO_4^{2-}(aq)+4H^+(aq)+2e^-\rightarrow H_2SO_3(aq)+H_2O(l)..[2]

Adding [1] and [2]:

SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)

The final balanced equation is :

SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)

4 0
3 years ago
Describe what the specific heat capacity (c) tells us about a substance. *<br> Your answer
NeX [460]

Answer:

it tells us of the specific amount of energy required to change the state of one mole of a substance either from solid to liquid or liquid to gas and vice versa without change in temperature

5 0
4 years ago
The average speed of oxygen molecules in air is about ____. (1 point) 0 km/h 170 km/h 1700 km/h 17,000 km/h
LenKa [72]

The average speed is calculated using the following formulaspeed = \sqrt{\frac{3kT}{m} }


Where

k = 1.381 X  10^{-23} J / K

T = 298 K [room temperature]

m = mass of each molecule of oxygen

mass of one mole of oxygen molecules = 32 g / mol

mass of one molecule of oxygen will be = \frac{32}{6.023 X 10^{23} }

mass of one molecule of oxygen will be = 5.31 X 10^{-23} g = 5.31 X 10^{-26} kg

putting values

average speed = \sqrt{\frac{3 X 1.381 X  10^{-23} X 298}{5.31 X 10^{-26} kg} }

Average speed = 482.19 m / s

average speed = 1735.8 km / h

so approx = 1700 km/h

4 0
3 years ago
Read 2 more answers
Which of the following concerning the effects of temperature and pressure on solubility is/are correct?
just olya [345]

Answer:

None of the options are correct.

Explanation:

1) when the temperature of the solution is increased the solubility of the gas in the liquid decreases , hence option 1 is incorrect.

2)The heat released by the dissolution of an ionic compound in water is heat of hydration of the compound and is independent of the initial temperature of the solution.

3) The solubility of a liquid in water is not affected significantly by the pressure changes in the system as gases only have a significant cahne in solubility with change in pressure.

5 0
3 years ago
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