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vladimir2022 [97]
3 years ago
7

Can someone help me with my chemistry problem?

Chemistry
1 answer:
insens350 [35]3 years ago
8 0

Answer:

D. 108g of water

Explanation:

16g CH4 produces 2(18)g of H20

1g CH4 produces \frac{36}{16}g of H2O

48g CH4 produces \frac{36}{16}×48

                                108g of H20

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What will occur if the velocity of the gas molecules colliding with the sides of the container increases?
yanalaym [24]

The pressure  of the gas will increases

6 0
4 years ago
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How did the building of granaries indicate that Harappan civilization was economically strong?
kvasek [131]

It showed that the richest Harappan citizens had excess food to trade or sell. It showed that Harappa could store excess food to save, sell, or trade with others.

5 0
3 years ago
commercial cold packs consist of solid NH4NO3 and water. In a coffee-cup calorimeter, 5.60g NH4NO3 is dissolved in 100g of water
fgiga [73]

Answer:

-1.37 kJ/mol

Explanation:

The expression for the calculation of the enthalpy of dissolution of [tex[NH_4NO_3[/tex] is shown below as:-

\Delta H=m\times C\times \Delta T

Where,  

\Delta H  is the enthalpy of dissolution of [tex[NH_4NO_3[/tex]

m is the mass

C is the specific heat capacity

\Delta T  is the temperature change

Thus, given that:-

Mass of ammonium nitrate = 5.60 g

Specific heat = 4.18 J/g°C

\Delta T=17.9-22.0\ ^0C=-4.1\ ^0C

So,  

\Delta H=-1.25\times 4.18\times 3.9\ J=-95.9728\ J

Negative sign signifies loss of heat.  

Also, 1 J = 0.001 kJ

So,  

\Delta H=-0.096\ kJ

Also,

Molar mass of [tex[NH_4NO_3[/tex] = 80.043 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{5.60\ g}{80.043 \ g/mol}

Moles= 0.06996\ mol

Thus, \Delta H=-\frac{0.096}{0.06996}\ kJ/mol=-1.37\ kJ/mol

6 0
4 years ago
Sodium phosphate dissolves as follows: na3po4(s) → 3na (aq) po4-(aq). How many moles of na3po4 are required to make 1. 0 l of so
bezimeni [28]

The 0.05 moles of Na_{3}PO_{4} required to make 1 L of solution in which the Na concentration is 0. 15 M.

Calculation,

The Sodium phosphate dissolves as follows:

Na_{3}PO_{4}(s) → 3Na^{+} (aq)+PO_{4}^{-} (aq)

To make 1. L of solution in which the  Na^{+concentration is 0. 15 M

The morality  of Na^{+= 0.15 M = number of moles / volume in lit

The morality of Na^{+= 0.15 M = number of moles /1 Lit

number of moles of Na^{+ = 0.15 mole

The mole ratio is 1: 3

It means, the 1 mole of Na_{3}PO_{4}(s) required to form 3 mole of Na^{+

So, to form 0.15 mole of Na^{+  = 1×0.15 / 3 moles of Na_{3}PO_{4}(s)required.

Hence, number of moles of Na_{3}PO_{4}(s) required = 0.05 moles.

learn about moles

brainly.com/question/26416088

#SPJ4

6 0
2 years ago
What is the density of lead (in g/cm^3 3 ) if a rectangular bar measuring 0.500 cm in height, 1.55 cm in width, and 25.00 cm in
Viktor [21]

Answer:

Density = 11.4 g/cm³

Explanation:

Given data:

Density of lead = ?

Height of lead bar = 0.500 cm

Width of lead bar = 1.55 cm

Length of lead bar = 25.00 cm

Mass of lead bar = 220.9 g

Solution:

Density = mass/ volume

Volume of bar = length × width × height

Volume of bar = 25.00 cm × 1.55 cm × 0.500 cm

Volume of bar = 19.4 cm³

Density of bar:

Density = 220.9 g/ 19.4 cm³

Density = 11.4 g/cm³

3 0
3 years ago
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