Can someone help me with my chemistry problem?
1 answer:
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Answer:
-1.37 kJ/mol
Explanation:
The expression for the calculation of the enthalpy of dissolution of [tex[NH_4NO_3[/tex] is shown below as:-
Where,
is the enthalpy of dissolution of [tex[NH_4NO_3[/tex]
m is the mass
C is the specific heat capacity
is the temperature change
Thus, given that:-
Mass of ammonium nitrate = 5.60 g
Specific heat = 4.18 J/g°C
So,
Negative sign signifies loss of heat.
Also, 1 J = 0.001 kJ
So,
Also,
Molar mass of [tex[NH_4NO_3[/tex] = 80.043 g/mol
The formula for the calculation of moles is shown below:
Thus,
Thus,
The 0.05 moles of required to make 1 L of solution in which the
concentration is 0. 15 M.
Calculation,
The Sodium phosphate dissolves as follows:
→
To make 1. L of solution in which the concentration is 0. 15 M
The morality of = 0.15 M = number of moles / volume in lit
The morality of = 0.15 M = number of moles /1 Lit
number of moles of = 0.15 mole
The mole ratio is 1: 3
It means, the 1 mole of required to form 3 mole of
So, to form 0.15 mole of = 1×0.15 / 3 moles of
required.
Hence, number of moles of required = 0.05 moles.
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