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1 year ago

In one to two sentences, identify the type of model shown and describe the atomic sructure of a molecule of water.

1 answer:

6 0

The model shown is a ball and stick model of a water molecule showing atomic structure of a water molecule consisting of two atoms of hydrogen bonded to an oxygen atom.

<h3>What are models?</h3>

Models are representations in the form of diagrams, pictures, or illustration of concepts, ideas, or structures of other objects.

In science, models are used to represent molecules and atoms of substances.

Some common models used in chemistry to represent the molecules of substances are:

ball and stick model
space-filling models

The model shown is a ball and stick model of a water molecule.

The atomic structure of a water molecule consists of two atoms of hydrogen bonded to an oxygen atom.

In conclusion, models are used to represent the structure of other substances or concepts.

Learn more about ball and stick model at: brainly.com/question/4300427

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1. element with three occupied energy levels and<br> one valence electron

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Answer:

Potassium (K) = (2,8,8,1)

This is the element that has three(3) filled energy level and one valence electron

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2 years ago

5. If 1 g of a gas occupies a volume of 300 mL at STP, what is the molecular weight of the gas?

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Answer:

74,67 gr/mol

Explanation:

At STP 1 mole of an ideal gas has volume of 22,4 L. Since we know the volume of the gas we can find the number of moles of the gas. (300 mL=0,3 L)

n=0,3L/22,4 L=0,01339 mol

Since we know weight of the gas as 1 g, we can find the molecular weight as;

MW=1 g/0,01339 mol =74,67 gr/mol

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2 years ago

A wooden artifact from an ancient tomb contains 60% of the carbon-14 that is present in living trees. How long ago was the artif

noname [10]

Answer:

The age of the sample is 4224 years.

Explanation:

Let the age of the sample be t years old.

Initial mass percentage of carbon-14 in an artifact = 100%

Initial mass of carbon-14 in an artifact = $[A_o]$

Final mass percentage of carbon-14 in an artifact t years = 60%

Final mass of carbon-14 in an artifact = $[A]=0.06[A_o]$

Half life of the carbon-14 = $t_{1/2}=5730 years$

$k=\frac{0.693}{t_{1/2}}$

$[A]=[A_o]\times e^{-kt}$

$[A]=[A_o]\times e^{-\frac{0.693}{t_{1/2}}\times t}$

$0.60[A_o]=[A_o]\times e^{-\frac{0.693}{5730 year}\times t}$

Solving for t:

t = 4223.71 years ≈ 4224 years

The age of the sample is 4224 years.

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3 years ago

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