1.506 × 10²³ carbon atoms
Explanation:
First we calculate the number of moles of calcium carbonate (CaCO₃) contained in 25 g.
number of moles = mass / molecular weight
number of moles of CaCO₃ = 25 / 100 = 0.25 moles
Now we make use of Avogadro's number which tell us that we have 6.022 × 10²³ molecules (or atoms) in one mole of substance.
Now in our case:
if in 1 mole of CaCO₃ we have 1 × 6.022 × 10²³ carbon atoms
then in 0.25 moles of CaCO₃ we have X carbon atoms
X = (0.25 × 1 × 6.022 × 10²³) / 1
X = 1.506 × 10²³ carbon atoms
Learn more:
Avogadro's number
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Dispersion forces are the only type of intermolecular force operating between non-polar molecules, for example, dispersion forces operate between hydrogen (H2) molecules, chlorine (Cl2) molecules, carbon dioxide (CO2) molecules, nitrogen tetroxide (N2O4) molecules and methane (CH4) molecules.
www.ausetute.com.au/intermof.html
95.21 grams.
Add the atomic mass of each element present. (If there is more than one atom of an element, multiply the element's atomic mass by the number of that element's atoms.)