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Strike441 [17]
1 year ago
13

In one to two sentences, identify the type of model shown and describe the atomic sructure of a molecule of water.

Chemistry
1 answer:
QveST [7]1 year ago
6 0

The model shown is a ball and stick model of a water molecule showing  atomic structure of a water molecule consisting of two atoms of hydrogen bonded to an oxygen atom.

<h3>What are models?</h3>

Models are representations in the form of diagrams, pictures, or illustration of concepts, ideas, or structures of other objects.

In science, models are used to represent molecules and atoms of substances.

Some common models used in chemistry to represent the molecules of substances are:

  • ball and stick model
  • space-filling models

The model shown is a ball and stick model of a water molecule.

The atomic structure of a water molecule consists of two atoms of hydrogen bonded to an oxygen atom.

In conclusion, models are used to represent the structure of other substances or concepts.

Learn more about ball and stick model at: brainly.com/question/4300427

#SPJ1

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A glass flask whose volume is 1000 cm3 at a temperature of 0.800 C is completely filled with mercury at the same temperature. Wh
ira [324]

Answer: the coefficient of volume expansion of glass = 0.86/(1000 * 52) = 0.00001654 per degree.

Explanation:

Original volume of mercury = 1000 cm3.

The final volume of mercury considering its volume expansion quotient = 1000 + 1000*(1.8*10^-4 *52) = 1000 + 9.36 = 1009.36 cm^3

Considering the glass as a non expanding substance, the complete excess volume of 9.36 cm3 of mercury should have overflown the container, but due to the expansion of glass, the capacity of mercury containment increases and so a lesser amount of mercury flows out.

The amount of mercury that actually flowed out = 8.50 cm3.

So, the expansion of the glass container = 9.36-8.50 = 0.86 cm3.

Using the formula for coefficient of expansion,

coefficient of volume expansion of glass = 0.86/(1000 * 52) = 0.00001654 per degree.

5 0
3 years ago
If a substance is composed entirely of one type of atom, it is known as a(n) _______.
Firlakuza [10]
<span>A substance is composed entirely of one type of atom, it is known as a Chemical element
because mixture contain more than one type of atom and it cannot be neutron or isotope
so correct option is B
hope it helps</span>
8 0
3 years ago
Gunther needs a 75% concentrated solution. When making his solution at room temperature, he could only make a
Rzqust [24]

Heat the solution to dissolve the solute

5 0
3 years ago
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The powder mixture (Cu, Al and Fe) = 10g was oxidized from sufficient chloride acid. 1) What are the possible reactions to the p
Mandarinka [93]

Answer:

1) 2Al + 6HCl ⟶ 2AlCl₃ + 3H₂

    Fe + 2HCl ⟶ FeCl₂ + H₂

2) Cu = 2.5 g; Al = 3.5 g; Fe = 4.0 g  

Explanation:

1) Possible reactions

2Al + 6HCl ⟶ 2AlCl₃ + 3H₂

Fe + 2HCl ⟶ FeCl₂ + H₂

2) Mass of each metal

a) Mass of Cu

The waste was the unreacted copper.

Mass of Cu = 2.5 g

b) Masses of Al and Fe

We have two relations :

Mass of Al + mass of Fe = 10 g - 2.5 g = 7.5 g

H₂ from Al + H₂ from Fe = 6.38 L at NTP

i) Calculate the moles of H₂

NTP is 20 °C and 1 atm.

\begin{array}{rcl}pV & = & n RT\\\text{1 atm} \times \text{6.38 L} & = & n \times 0.08206 \text{ L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{293.15 K}\\6.38 & = & 24.06n \text{ mol}^{-1} \\n & = & \dfrac{6.38}{24.06 \text{ mol}^{-1} }\\\\ & = & \text{0.2652 mol}\\\end{array}

(ii) Solve the relationship

 Let x = mass of Al. Then

7.5 - x = mass of Fe

Moles of Al = x/27

Moles of Fe = (7.5 - x)/56

Moles of H₂ from Al = (3/2) × Moles of Al = (3/2) × (x/27) = x /18

Moles of H₂ from Fe = (1/1) × Moles of Fe = (7.5 - x)/56

∴ x/18 + (7.5 - x)/56 = 0.2652

    56x + 18(7.5 - x) = 267.3

      56x + 135 - 18x = 267.3

                        38x = 132.3

                            x = 3.5 g

Mass of Al = 3.5 g

Mass of Fe = 7.5 g - 3.5 g = 4.0 g

The masses of the metals are Cu = 2.5 g; Al = 3.5 g; Fe = 4.0 g

4 0
3 years ago
When a gas is pumped into a small rigid container the pressure inside the container increases as more particles are added. If th
marysya [2.9K]
Since the container of the gas is rigid, the volume of the gas will remain constant. Therefore, when the number of particles were decreased in half then the pressure will also be half of the original given they both are subjected to the same temperature.

PV = nRT

V, T and R are constants so they can be lumped together to a constant k.

P/n = k
P1/n1 = P2/n2

since n2 = n1/2
P1/n1 = P2/<span>n1/2</span>
P2 = P1/2
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3 years ago
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