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umka2103 [35]
3 years ago
13

HELLLLP PLS 25 POINTS AND BRAINLIEST

Chemistry
2 answers:
SashulF [63]3 years ago
5 0

During a nuclear reaction, fuel rods generate a tremendous amount of heat. ... Problems cooling these pools have officials worried that the spent rods could ... appear to be related to one or more of the spent fuel storage pools at the plant. ... These fission byproducts are also very radioactive.

does that kind of help a little?

Akimi4 [234]3 years ago
5 0

Answer:

They are scheduled for deep underground burial

Explanation:

Honestly none of these answers are correct in a sense.

They are no longer radioactive - This one is absolutely false since spent fuel rods remain dangerously radioactive for about for about 10,000 years

They contain only one type of isotope of the fuel (uranium) - There will be some 235 isotopes as well as some 238. Other isotopes might be present as well but only in very small amounts.

They usually remain radioactive for less than 100 years - As mentioned above, spent fuel rods remain dangerously radioactive for about 10,000 years.

They are scheduled for deep underground burial - This answer is probably the best as it it somewhat true. In the 1980's there was a plan launched by the federal government to bury spent fuel below Yucca Mountain in Nevada. However, this project was later called off to think of a better means of containment.

However...

Scandinavia and Finland have already approved an approach known as "deep storage" and have already begun to work on their own sites.

~Hope this helps!~

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You have 2.7 moles of carbon. How many atoms do you have?
Gelneren [198K]

Answer:

1.63 × 10²⁴ atoms.

Explanation:

To calculate the number of atoms (N) contained in 2.7moles of carbon, we multiply the number of moles (n) by Avogadro's number (6.02 × 10²³).

That is, N = n × nA

Where;

N = number of atoms

n = number of moles (mol)

nA = Avogadro's numbe

N = 2.7 × 6.02 × 10²³

N = 16.254 × 10²³

N = 1.63 × 10²⁴ atoms.

Hence, there are 1.63 × 10²⁴ atoms in 2.7moles of Carbon.

4 0
2 years ago
Calcule la densidad del hidrógeno H2 en g/L a 327 mm Hg y 48ºc
tankabanditka [31]
<h3>The density of H₂ = 0.033 g/L</h3><h3>Further explanation</h3>

In general, the gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

where  

P = pressure, atm , N/m²

V = volume, liter  

n = number of moles  

R = gas constant = 0.082 l.atm / mol K (P= atm, v= liter),or 8,314 J/mol K (P=Pa or N/m², v= m³)

T = temperature, Kelvin  

n = N / No  

n = mole  

No = Avogadro number (6.02.10²³)  

n = m / MW

m = mass  

MW = molecular weight

For density , can be formulated :

\tt \rho=\dfrac{P\times MW}{R\times T}

P = 327 mmHg = 0,430263 atm

R = 0.082 L.atm / mol K

T = 48 ºC = 321.15 K

MW of H₂ =  2.015 g/mol

The density :

\rho=\dfrac{0,430263\times 2.015 }{0.082\times 321.15}\\\\\rho=0.033~g/L

4 0
2 years ago
A cracker crushed in water will test positive with iodine but negative with benedict’s solution. A
german
A cracker which contains starch,is test positive with iodine solution but not Benedict's solution. This is because Benedict's solution is used to test for reducing sugars like glucose,galactose,fructose,maltose and lactose.In this case, the cracker is added with amylase enzyme which hydolyses starch into maltose,thus benedict's solution is test positive
7 0
3 years ago
The mass of 1.63x10^21 silicon atoms is how many grams
gladu [14]
<span>Lyle stirs 5.0 grams of salt into a beaker of water. He then adds 15.0 grams of pure iodine to the mixture. If the total mass of the new mixture is 225 grams, what is the mass of the water
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6 0
3 years ago
A gas mixture consists of 60.0% Ar, 30.0% Ne, and 10.0% Kr by volume. If the pressure of this gas mixture is 80.0 kPa, what is t
Nat2105 [25]

Answer: The partial pressure of Argon , Neon and krypton are 48 kPa , 24 kPa and 8 kPa respectively.

Explanation:

According to Raoult's Law , the partial pressure of each component in the solution is equal to the total pressure multiplied by its mole fraction. It is mathematically expressed as

p_A=x_A\times P_{total}

where, p_A = partial pressure of component A

x_A = mole fraction of A

P_{total} = total pressure

mole fraction of Ar = \frac{\text {Moles of Ar}}{\text {total moles}}=\frac{60.0}{60.0+30.0+10.0}=0.6

p_{Ar}=0.60\times 80.0kPa=48kPa

mole fraction of Ne = \frac{\text {Moles of Ne}}{\text {total moles}}=\frac{30.0}{60.0+30.0+10.0}=0.30

p_{Ne}=0.30\times 80.0kPa=24kPa

mole fraction of Kr = \frac{\text {Moles of Kr}}{\text {total moles}}=\frac{10.0}{60.0+30.0+10.0}=0.10

p_{Kr}=0.10\times 80.0kPa=8kPa

4 0
3 years ago
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