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3 years ago

HELLLLP PLS 25 POINTS AND BRAINLIEST

2 answers:

5 0

During a nuclear reaction, fuel rods generate a tremendous amount of heat. ... Problems cooling these pools have officials worried that the spent rods could ... appear to be related to one or more of the spent fuel storage pools at the plant. ... These fission byproducts are also very radioactive.

does that kind of help a little?

Akimi4 [234]3 years ago

5 0

Answer:

They are scheduled for deep underground burial

Explanation:

Honestly none of these answers are correct in a sense.

They are no longer radioactive - This one is absolutely false since spent fuel rods remain dangerously radioactive for about for about 10,000 years

They contain only one type of isotope of the fuel (uranium) - There will be some 235 isotopes as well as some 238. Other isotopes might be present as well but only in very small amounts.

They usually remain radioactive for less than 100 years - As mentioned above, spent fuel rods remain dangerously radioactive for about 10,000 years.

They are scheduled for deep underground burial - This answer is probably the best as it it somewhat true. In the 1980's there was a plan launched by the federal government to bury spent fuel below Yucca Mountain in Nevada. However, this project was later called off to think of a better means of containment.

However...

Scandinavia and Finland have already approved an approach known as "deep storage" and have already begun to work on their own sites.

~Hope this helps!~

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Answer:

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2 years ago

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To study a key fuel-cell reaction, a chemical engineer has 20.0-L tanks of H₂ and of O₂ and wants to use up both tanks to form 2

Lapatulllka [165]

the pressure needed on H2 tank is 34.9477319atm and the pressure needed in O2 tanks is 16.7690007atm .

Given , to study a key fuel-cell reaction , a chemical engineer has 20.0L tanks of H2 and O2 and wants to use up both tanks to form 28.0mol of water at 23.8°C .

the reaction of the fuel cell is given by ,

H2(g) +1/2 O2 ( g) →H2O

Moles of H2 required = 28 mol

moles of O2 required = 14mol

Now according to van der waals equation ,

p= (nRT/ V-nb) - an^2 / V^2

for H2 , a = 0.2453L^2bar /mol^2 , b= 0.02651L/mol

P for H2

= (28×0.0821×296.8/20-28×0.02651 ) -(0.2456 ×28×28/20×20)

P for H2 = 35.4291079-0.481376 = 34.9477319 atm

for O2 , a = 1.38L^2bar/mol^2 , b = 0.03186L/mol

P for O2 = (14×0.0821×296.8 /20-14×0.03186) - (1.382×14×14/20×20)

P for O2 = 17.4461807 - 0.67718 =16.7690007 atm

Hence , the pressure needed on H2 tank is 34.9477319atm and the pressure needed in O2 tanks is 16.7690007atm .

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11 months ago

This increase in blood pHpH due to hyperventilation disrupts O2O2 transport by causing the deprotonation of various residues of

Genrish500 [490]

The question is incomplete as it does not have the options which has been provided in the attachment.

Answer:

1. sudden decrease

2. Respiratory alkalosis

Explanation:

Hyperventilation is a condition caused by the excess removal of the CO₂ from the blood which leads to the decrease in the pCO₂ of the arteries.

This decrease can cause fainting and death of the individual due to the malfunctioning of the body parts, especially the brain.

The decrease in the CO₂ amount of the blood causes the formation of bicarbonate and H⁺ ions which leads to respiratory alkalosis.

Therefore the selected options are correct.

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3 years ago

Vapor pressure can be described as: A) the temperature at which bubbles of vapor appear in a liquid. B) the pressure exerted on

Vanyuwa [196]

Answer: Option (D) is the correct answer.

Explanation:

Vapor pressure is defined as the pressure exerted by the vapors which are present on the surface of a liquid.

For example, vapor pressure of water at room temperature is 0.0313 atm.

On the other hand, the temperature at which the vapor pressure of a liquid equals atmospheric pressure is known as boiling point.

For example, boiling point of water at room temperature is $100^{o}C$ .

Thus, we can conclude that vapor pressure can be described as the pressure exerted by a gas above the surface of its liquid.

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3 years ago

Kerosene, a common space-heater fuel, is a mixture of hydrocarbons whose "average" formula is C₁₂H₂₆.

padilas [110]

The calculated enthalpy of formation of kerosene is 365.4 kJ and heat produced is 78650.3 kJ

For this, we need the normal enthalpy of formation given below

ΔH∘f(CO2)=−393.5kJ/molΔH∘f(H2O)\s=−241.8kJ/molΔH∘f(O2)=0kJ/mol

We shall now determine the enthalpy of kerosene formation:

H rxn = 24 mol H f (CO2) + 26 mol H f (H2O) + 2 mol H f (C12H26) + 37 mol H f (O2) + 1.50 104 kJ = 9444 kJ + 6286.8 kJ + 1500 kJ 2 mol H f (C12H26) = 730.8 kJ H f (C12H26) = 365.4 kJ

Kerosene has a density of 0.74 g/mL.

Kerosene volume (V) equals 0.63 gallons, or 0.63 x 3785.4, or 2384. 8 mL.

We shall now calculate the mass (m) of kerosene:

ρ=mVm\s=ρ×Vm\s=0.749g/mL×2384.mLm\s=1786.2g

We shall now discover the heat that 1786 generated.

Two grams of kerosene

Kerosene's molar mass is 170.33 g/mol.

The mass of two moles of kerosene is equal to 2*170.33*340.66g.

1.50104kJ of heat are generated by 340.66 g of kerosene.

1786 produced heat.

Kerosene 2 grams = 1.50 104 kJ 340.66 1786.2 g = 78650.3 kJ

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1 year ago