A.Genus And Species. FOR EXAMPLE HUMAN, Genus-homo And Species-sapiens Which For Homo Sapiens.
Answer:
158.5g Zn are produced
Explanation:
To solve this question we have to find the moles of Aluminium. With the moles of Aluminium and the balanced reaction we can find the moles of Zn and its mass as follows:
<em>Moles Al -Molar mass: 26.98g/mol</em>
43.6g Al* (1mol/26.98g) = 1.616 moles Al
<em>Moles Zn:</em>
1.616 moles Al * (3mol Zn / 2mol Al) =
2.424 moles Zn are produced
<em>Mass Zn -Molar mass: 65.38g/mol-</em>
2.424 moles Zn * (65.38g / mol) =
<h3>158.5g Zn are produced</h3>
Answer:
I think the answer is: one element and one compound
Explanation:
I'm really sorry if it's wrong.
Answer : The solubility of this compound in g/L is
.
Solution : Given,
![K_{sp}=2.42\times 10^{-11}](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D2.42%5Ctimes%2010%5E%7B-11%7D)
Molar mass of
= 114.945g/mole
The balanced equilibrium reaction is,
![MnCO_3\rightleftharpoons Mn^{2+}+CO^{2-}_3](https://tex.z-dn.net/?f=MnCO_3%5Crightleftharpoons%20Mn%5E%7B2%2B%7D%2BCO%5E%7B2-%7D_3)
At equilibrium s s
The expression for solubility constant is,
![K_{sp}=[Mn^{2+}][CO^{2-}_3]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BMn%5E%7B2%2B%7D%5D%5BCO%5E%7B2-%7D_3%5D)
Now put the given values in this expression, we get
![2.42\times 10^{-11}=(s)(s)\\2.42\times 10^{-11}=s^2\\s=0.4919\times 10^{-5}=4.919\times 10^{-6}moles/L](https://tex.z-dn.net/?f=2.42%5Ctimes%2010%5E%7B-11%7D%3D%28s%29%28s%29%5C%5C2.42%5Ctimes%2010%5E%7B-11%7D%3Ds%5E2%5C%5Cs%3D0.4919%5Ctimes%2010%5E%7B-5%7D%3D4.919%5Ctimes%2010%5E%7B-6%7Dmoles%2FL)
The value of 's' is the molar concentration of manganese ion and carbonate ion.
Now we have to calculate the solubility in terms of g/L multiplying by the Molar mass of the given compound.
![s=4.919\times 10^{-6}moles/L\times 114.945g/mole=565.414\times 10^{-6}g/L](https://tex.z-dn.net/?f=s%3D4.919%5Ctimes%2010%5E%7B-6%7Dmoles%2FL%5Ctimes%20114.945g%2Fmole%3D565.414%5Ctimes%2010%5E%7B-6%7Dg%2FL)
Therefore, the solubility of this compound in g/L is
.