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3 years ago

Determine the answer to the following equation with correct number of significant figures: (4.123 × 0.12) + 24.2 =

Chemistry

1 answer:

rewona [7]3 years ago

8 0

The value of the given equation i.e. (4.123 × 0.12) + 24.2 is 24.7.

Given that,

The equation is (4.123 × 0.12) + 24.2.

According to the BODMAS rule, first, we have to multiply 4.123 with 0.12 after that add the 24.2 to the value that comes.

So,

= (4.123 × 0.12) + 24.2

= 0.49476 + 24.2

= 24.69

= 24.70

Therefore we can conclude that the value of the given equation i.e. (4.123 × 0.12) + 24.2 is 24.7.

Learn more: brainly.com/question/24169758

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how are ionic bonds formed? a. by the disintegration of one or more electronsb. by the sharing of one or more electrons between

Greeley [361]

The correct answer is: by the transfer of one or more electrons from one atom to another.

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4 years ago

Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 1.20 MJ 1

mars1129 [50]

Answer : The mass of liquid sodium needed are, $3.17\times 10^3g$

Explanation :

First we have to calculate the number of moles of liquid sodium.

$q=n\times c\times (\Delta T)$

where,

q = heat absorb = 1.20 MJ = 1.20 × 10⁶ J

n = number of moles of liquid sodium = ?

c = specific heat capacity = $30.8J/mol.K$

$\Delta T$ = change in temperature = $10.0^oC=273+10.0=283K$

Now put all the given values in the above formula, we get:

$1.20\times 10^6J=n\times 30.8J/mol.K\times 283K$

$n=137.7mol$

Now we have to calculate the mass of liquid sodium.

Molar mass of Na = 23 g/mol

$\text{Mass of Na}=\text{Moles of Na}\times \text{Molar mass of Na}$

$\text{Mass of Na}=137.7mol\times 23g/mol=3167.1g=3.17\times 10^3g$

Therefore, the mass of liquid sodium needed are, $3.17\times 10^3g$

3 0

4 years ago

Can someone pls help me I appreciate it

Feliz [49]

Answer:

b, e, f

Explanation:

3 0

4 years ago

Why was it important to let the solution cool down before conducting the titration experiment?

Papessa [141]

Answer:

The pH range, reaction rate, accuracy and solubility are affected by the temperature.

Explanation:

Hello,

Temperature is factor affecting how solutions behave, thus, it could modify the pH range (change in color values) for an indicator in the presence of a base or an acid, since the kinetics behind the change of color is modified maybe decreasing or increasing the aforesaid range. Next, temperature usually increases the reaction rate, that's why the change in color could become faster or out of the proper change range. Then, in titration we use temperature-sensitive glassware which could expand due to high temperatures and subsequently turning out into wrong measurements. Finally, solubility is affected by the temperature, since the molecules are allowed to interact more effectively, that's we must make sure that they're completely dissolved at room temperature while titrating.

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6 0

4 years ago

Suppose 2.90g of nickel(II) iodide is dissolved in 150ml of a 0.70M aqueous solution of potassium carbonate. Calculate the final

ehidna [41]

Answer:

0.124 M.

Explanation:

Hello!

In this case, since the nickel iodide has the following formula:

NiI₂

So its molar mass is 312.5023 g/mol, in order to compute the molarity of the iodide anion, we first need the moles in 2.90 g:

$n_{NiI_2}=2.90g*\frac{1molNiI_2}{312.5023 gNiI_2} =0.00927molNiI_2$

Now, since one mole of nickel(II) iodide contains two mole of iodide anions, we infer there are 0.0186 moles of iodide cations. Moreover, since the molarity is computed by dividing the moles of those ones by the volume of the solution in liters, 150 mL (0.150 L) as it does not change, it turns out:

$M=\frac{0.0186molI^-}{0.150L}\\\\M=0.124M$

Best regards!

8 0

3 years ago