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Sedbober [7]
3 years ago
5

Determine the answer to the following equation with correct number of significant figures: (4.123 × 0.12) + 24.2 =

Chemistry
1 answer:
rewona [7]3 years ago
8 0

The value of the given equation i.e. (4.123 × 0.12) + 24.2 is 24.7.

Given that,

  • The equation is (4.123 × 0.12) + 24.2.

According to the BODMAS rule, first, we have to multiply 4.123 with 0.12 after that add the 24.2 to the value that comes.

So,

= (4.123 × 0.12) + 24.2

= 0.49476 + 24.2

= 24.69

= 24.70

Therefore we can conclude that the value of the given equation i.e. (4.123 × 0.12) + 24.2 is 24.7.

Learn more: brainly.com/question/24169758

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Convert the following a) 8.43 Km/week to millimeters/second
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Answer:

13.93849 millimeters/second

Explanation:

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3 years ago
Explain, in terms of electrons, why the bonding in strontium sulfide, SrS, is similar to the bonding in magnesium bromide, MgBr2
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5 0
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Suppose Gabor, a scuba diver, is at a depth of 15m15m. Assume that: The air pressure in his air tract is the same as the net wat
alexandr1967 [171]

Answer:

The ration of molar concentration is "2.5".

Explanation:

The given values are:

Average density of salt water,

= 1.03 \ g/cm^3

Net pressure,

= 2.00 \ atm

Increase in pressure,

= 1.00 \ atm

Now,

The under water pressure will be:

=  \frac{15 \ m}{10}\times 1 \ atm +1 \ atm

=  1.5\times 1+1

=  1.5+1

=  2.5 \ atm

hence,

The ratio will be:

=  \frac{(\frac{n}{V})_{15m} }{(\frac{n}{V})_{surface} }

or,

=  \frac{P}{P_s}

=  \frac{2.5}{1}

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7 0
3 years ago
Determine the percentage composition of Ptl2
Hitman42 [59]

Answer:

Percent Composition

1. Find the molar mass of all the elements in the compound in grams per mole.

2. Find the molecular mass of the entire compound.

3. Divide the component's molar mass by the entire molecular mass.

4. You will now have a number between 0 and 1. Multiply it by 100% to get percent composition.

7 0
2 years ago
An experiment produced 0.10 g CO2 with a volume of 0.056 L at STP. If the accepted density of CO2 at STP is 1.96 g/L, what is th
Mandarinka [93]
The experimental density of CO2 at STP is 0.10/0.056=1.78 g/L. The percent error equals to (1.96-1.78)/1.96*100%=9.18%. So the answer is 9.18%.
3 0
3 years ago
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