7 × 10² pounds of Cl₂ would be produced in a typical 8-h operating day.
<h3>What is Stoichiometry ?</h3>
Stoichiometry helps us use the balanced chemical equation to measures quantitative relationships and it is to calculate the amount of products and reactants that are given in a reaction.
<h3>What is Balanced chemical equation ?</h3>
The balanced chemical equation is the equation in which the number of atoms on the reactants side is equal to the number of atoms on the product side in an equation.
2Cl⁻ (aq) → Cl (g) + 2e⁻
According to stoichiometry, moles of Cl₂

= 4477 moles
Pounds Cl₂

= 7 × 10² lb
Thus from the above conclusion we can say that 7 × 10² pounds of Cl₂ would be produced in a typical 8-h operating day.
Learn more about Stoichiometry here: brainly.com/question/14935523
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Answer:
a. NH₃ : base
CH₃COOH (acetic acid) : acid
NH₄⁺ : conjugate acid
CH₃COO⁻ : conjugate base
b. HClO₄ (perchloric acid) : acid
NH₃ : base
ClO₄⁻ : conjugate base
NH₄⁺ : conjugate acid
Hope this helps.
Use the concentration to obtain the moles. I am assuming you mean to write capital M. because little m means molality.
So, first convert the ml into Liters and then into moles, then moles to grams using the molar mass (just adding the values of each atom from the periodic table. )
Molar mass= 12 (12.0) + 22 (1.01)+ 11 (16.0)= 342 grams/mole
300 ml (1 liter/ 1000 mL) x (0.50 moles/ 1 Liter) x (342 grams/ 1 mole)= 51.3 grams