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White raven [17]
2 years ago
5

A vector is something with a magnitude and direction. Explain in 1 or 2 sentences the analogy between a vector and the voltage d

isplay on a handheld multimeter.
Physics
1 answer:
soldier1979 [14.2K]2 years ago
5 0

A vector is a mathematical object that has both magnitude and direction.  Both the vectors and analogue multimeter shows the magnitude as well as direction of the value that measures.

To find the answer, we have to know about the multimeters.

<h3>How vector is analogous with multimeters?</h3>
  • The formula for the magnitude of a vector, which may be written as |v|, can be used to determine the length of any given vector.
  • In other words, this amount is used to specify the distance between the vector's beginning and ending points.
  • The measurement of the angle produced using the horizontal line can be used to define the direction of a vector, which is nothing more than that.
  • An analog multimeter is a particular kind of multimeter that measures electrical quantities including voltage, current, and resistance using a needle on a scale.
  • A pointer that represents a particular value of the scale is used to display the result of any measurement made with an analog multimeter in analog form.
  • The amount to be measured is shown by the scale's reading.
  • The current value is shown by the needle's position on the scale.

Thus, we can conclude that, Both the vectors and analogue multimeter shows the magnitude as well as direction of the value that measures.

Learn more about multimeter here:

brainly.com/question/6850521

#SPJ4

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Answer:

the kinetic energy of a moving object has dependence on its mass and its velocity.

Explanation:

Above expression indicates that the kinetic energy is directly proportional to the mass of the object and to the square of the velocity of the object. Thus, the kinetic energy of a moving object has dependence on its mass and its velocity.

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3 years ago
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To regulate the intensity of light reaching our retinas, our pupils1 change diameter anywhere from 2 mm in bright light to 8 1 T
Ronch [10]

Correct question is;

To regulate the intensity of light reaching our retinas, our pupils1 change diameter anywhere from 2 mm in bright light to 8 mm in dim light. Find the angular resolution of the eye for 550 nm wavelength light at those extremes. In which light can you see more sharply, dim or bright?

Answer:

We'll see more sharply in dim light

Explanation:

If we consider diffraction through a circular aperture, then angular resolution is given by;

θ = 1.22λ/D

where:

θ is the angular resolution (radians) λ is the wavelength of light

D is the diameter of the lens' aperture.

Thus,

at diameter = 2mm = 2 x 10^(-3) m = 2 x 10^(6) nm

θ = (1.22 * 550)/(2 x 10^(6))

θ = 335.5 x 10^(-6) radians

Now, we need to convert this to arc seconds.

Thus;

1 arc second = 4.85 x 10^(-6) radians

So,θ = 335.5 x 10^(-6) radians = [335.5 x 10^(-6)]/[4.85 x 10^(-6)]

= 69.18 arc seconds

at diameter = 8mm = 8 x 10^(-3) m = 8 x 10^(6) nm

θ = (1.22 * 550)/(8 x 10^(6))

θ = 83.875 x 10^(-6) radians

Now, we need to convert this to arc seconds.

Thus;

1 arc second = 4.85 x 10^(-6) radians

So,θ = 83.875 x 10^(-6) radians = [83.875 x 10^(-6)]/[4.85 x 10^(-6)]

= 17.3 arc seconds

From the values of angular resolution gotten, we see that sharpness of image increases with increasing angular resolution. Thus, objects are sharper in dim light.

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air passing over an airplanes wing travels ,and therefore exerts pressure.than air traveling beneath the wing.
pickupchik [31]
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Two "particles" of air one going topside and the other underside meet again at the end of their motion across the wing. So, top side has to travel faster than bottom side. So top side has a lower "dynamic pressure" than underside.

And all that for 5 points ????????? (If I'm right, of course ... )
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Answer:

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