Hello =D
This problem is about cinematic
So
V = 45 mi/h
t = 2 h
Then 
V= X/t
X = V*t
Then
X = (45)*(2)
X = 90 mi
Best regards
 
        
             
        
        
        
Passengers in an aircraft are subject to the Normal and Gravity Force acting on them at a low 'orbit', so tiny that it can be many times compared to the same surface of the earth when speaking in general terms.
In a high orbit space vehicle or in the same space, said force decreases considerably or simply disappears, generating the sensation of weightlessness.
Remember that the Force of Gravity is given under the principle

Where,
G = Gravitational Universal constant
M = Mass of the planet
m = mass of the object
r = Distance from center of the planet
When the radius grows considerably the gravitational force begins to decrease.
 
        
             
        
        
        
Hello there! 
For this:
1). Convert 10km to meters! 
2). Convert the 30 minutes into seconds! 
3). Use the following formula to solve for speed! 
speed= distance/time 
Note: The units should automatically work out to m/s. :) 
My goal is to make sure you understand the problem, which is why I won't be giving you the answer. It'll be more work now, but less work in the future! :) 
Hope this helped!
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DISCLAIMER: I am not a professional tutor or have any professional background in your subject. Please do not copy my work down, as that will only make things harder for you in the long run. Take the time to really understand this, and it'll make future problems easier. I am human, and may make mistakes, despite my best efforts. Again, I possess no professional background in your subject, so anything you do with my help will be your responsibility. Thank you for reading this, and have a wonderful day/night!
        
             
        
        
        
The gravitational force between the Earth and the satellite (its "weight") is inversely proportional to the distance between the centers of both objects.
On the surface, their centers are separated by 1 Earth radius.
12,000 miles above the surface, they're separated by 4 Earth radiii.
(4/1) = 4
So after the move, the satellite's weight is (1/4²) = 1/16 of its surface weight.
(321 lb) / (16) = (20 and a hair) lb
The correct choice from the given list is " <em>>20 lb "</em> .