The acceleration exerted by the object of mass 10 kg is 
Answer: Option A
<u>Explanation:</u>
According to Newton’s second law of motion, any external force acting on a body will be directly proportional to the mass of the body as well as acceleration exerted by the body. So, the net external force acting on any object will be equal to the product of mass of the object with acceleration exerted by the object. Thus,

So,

As the force acting on the object is stated as 10 N and the mass of the object is given as 10 kg, then the acceleration will be

So, the acceleration exerted by the object of mass 10 kg is 
3 protons should be your answer
Answer:
The pressure exerted by camel feet is <u>2000 N/m²</u>.
Step-by-step explanation:
<h3><u>Solution</u> :</h3>
Here, we have given that ;
- Force applied on camel feet = 4000 N
- Total area of camel feet = 2 m²
We need to find the pressure exerted by camel feet.
As we know that :

Substituting all the given values in the formula to find the pressure exerted by camel feet.

Hence, the pressure exerted by camel feet is 2000 N/m².

Answer:
6ms^-1
Explanation:
Given that the frequency difference is
( 563- 544) = 19
So alsoThe wavelength of each wave is = v/f = 344 /544
and there are 19 of this waves
So it is assumed that each motorcycle has moved 0.5 of this distance
in one second thus the speed of the motorcycles will be
=> 19/2 x 344/544 = 6.0 m/s