1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AysviL [449]
1 year ago
5

________ is the enthalpy change when 1 mole of water is produced by the reaction of an acid and a base under standard conditions

.
Chemistry
1 answer:
Tatiana [17]1 year ago
7 0

Standard enthalpy change of neutralization is the enthalpy change when 1 mole of water is produced by the reaction of an acid and a base under standard conditions.

Enthalpy change of neutralization:

  • Every time enthalpy change of neutralization is calculated, one mole of water is produced.
  • Heat is released when an acid and an alkali react, hence enthalpy changes of neutralization are always negative.
  • The values are always quite comparable for reactions involving strong acids and alkalis, falling between -57 and -58 kJ mol-1.
  • If the reaction is the same in each case of a strong acid and a strong alkali, the enthalpy change is similar.

Learn more about the Enthalpy of neutralization with the help of the given link:

brainly.com/question/15347368

#SPJ4

You might be interested in
Butanoic acid + 1-pentanol
lutik1710 [3]

Answer: X is an Esther

Explanation: alcohol and carboxylate acid forms esters

7 0
2 years ago
A chemist has 2.0 mol of methanol (CH3OH). Molar mass of menthanol is 32.0g/mol. What is the mass, in grams, of the sample
Mademuasel [1]
2.0 mol x 32.0 g / 1 mol =
3 0
3 years ago
Can someone please help mee finish this?
zvonat [6]

Answer:

1.Physical. People measure water by themselves.

2.Physical. People chop wood.

Explanation:

(this is all I can answer for you. you have to explain it by yourself tho.)

I dont know if I'm correct so you should double check.

4 0
3 years ago
What is the energy of a photon of violet light with a frequency of 7.57x10^14 s^-1?
Eddi Din [679]

Answer:

ΔE = 5.02 x 10⁻¹⁹ j

Explanation:

ΔE (photon) = h·f = (6.63 x 10⁻³⁴ j·s)(7.57 x 10¹⁴ s⁻¹) = 5.02 x 10⁻¹⁹ j

h = Planck's Constant = 6.63 x 10⁻³⁴ j·s

f = frequency (given) = 7.57 x 10¹⁴ s⁻¹

6 0
2 years ago
What acid occurs naturally in the body and performs important regulatory functions
gtnhenbr [62]

Answer: carbonic acid

8 0
3 years ago
Read 2 more answers
Other questions:
  • Give the structures of both 1,2 and 1,4 adducts resulting from reaction of 1 equivalent of hcl with 1,3-pentadiene
    12·1 answer
  • QUESTION THREE
    12·1 answer
  • What is the easiest way to find the charge of an element using the periodic table?!?
    13·1 answer
  • Which compares the problem associated with radioactive waste created from generating electricity using fusion reactions to waste
    10·1 answer
  • How many grams of sulfur must be burned to give 100.0 g of So2
    5·1 answer
  • 2 Ag20 →4 Ag + O2 what reaction is this​
    11·1 answer
  • 0.0278, how many significant figures
    9·1 answer
  • The following information is to be used for the next 2 questions. In order to analyze for Mg and Ca, a 24-hour urine sample was
    9·1 answer
  • Which of below Is something not do with our natural resources? Recycle, reduce, or reuse?​
    7·2 answers
  • when 1.00 mol co and 3.00 mol h2 are placed into a 10.0 l vessel at 9270c and allowed to come to equilibrium, the mixture is fou
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!