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AysviL [449]
2 years ago
5

________ is the enthalpy change when 1 mole of water is produced by the reaction of an acid and a base under standard conditions

.
Chemistry
1 answer:
Tatiana [17]2 years ago
7 0

Standard enthalpy change of neutralization is the enthalpy change when 1 mole of water is produced by the reaction of an acid and a base under standard conditions.

Enthalpy change of neutralization:

  • Every time enthalpy change of neutralization is calculated, one mole of water is produced.
  • Heat is released when an acid and an alkali react, hence enthalpy changes of neutralization are always negative.
  • The values are always quite comparable for reactions involving strong acids and alkalis, falling between -57 and -58 kJ mol-1.
  • If the reaction is the same in each case of a strong acid and a strong alkali, the enthalpy change is similar.

Learn more about the Enthalpy of neutralization with the help of the given link:

brainly.com/question/15347368

#SPJ4

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The balanced combustion reaction for C6H6 is 2C6H6(l)+15O2(g)⟶12CO2(g)+6H2O(l)+6542 kJ If 8.600 g C6H6 is burned and the heat pr
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Answer : The final temperature of the water is, 22.5166^oC

Explanation : Given,

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First we have to calculate the moles of benzene.

\text{Moles of benzene}=\frac{\text{Mass of benzene}}{\text{Molar mass of benzene}}=\frac{8.600g}{78g/mol}=0.1103mole

Now we have to calculate the energy of combustion.

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According to reaction,

As, 2 moles of benzene gives 6542 kJ of energy on combustion.

So, 0.1103 mole of benzene gives \frac{6542 kJ}{2}\times 0.1103=360.7913kJ of energy on combustion.

Now we have to calculate the final temperature of the water.

Formula used : q_w=m_w\times c_w\times \Delta T=m_w\times c_w\times (T_{final}-T_{initial})

where,

q_w = heat released = 360.7913 kJ = 36079.13 J

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c_w = specific heat of water= 4.18J/g^oC

T_{final} = final temperature = ?

T_{initial} = initial temperature = 21^oC

Now put all the given values in the above formula, we get:

36079.13J=5691g\times 4.18J/g^oC\times (T_{final}-21^oC)

T_{final}=22.5166^oC

Therefore, the final temperature of the water is, 22.5166^oC

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