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NemiM [27]
3 years ago
15

Explain why isotopes of the same element behave differently in nuclear reactions but not in chemical reactions

Chemistry
2 answers:
Ymorist [56]3 years ago
5 0


Here are some different options of things you can expand upon in your response:

Isotopes of the same element differ only in neutron numbers. 

Nuclear reactions involve changes to the protons or neutrons in an atom’s nucleus, but not changes to its electrons.

Chemical reactions involve changes to the electrons in atoms, but not changes to its protons or neutrons.

Isotope behavior only differs when a reaction involves neutrons. 

a_sh-v [17]3 years ago
4 0
The nuclear core additionally contains neutrons. In customary concoction responses, neutron number does not make a difference. This is on the grounds that substance responses include just electrons. Be that as it may, in atomic responses, distinctive isotopes of a similar component can carry on in an unexpected way.
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Answer:

Explanation:

-mass of solute, density of solute, and volume of solution

-volume of solute, mass of solution, and density of solution

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Which of the following is an example of a mixture?
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B. the atmosphere is an example of a mixture
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A bathtub is filled with 100 L of water. A cat jumps in and the volume rises to 125 L. If the cat has a mass of
kirza4 [7]

Answer:

<h2>The answer is 3.2 g/L</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

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<h3>3.2 g/L</h3>

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3 0
3 years ago
Someone please answer this...
kupik [55]

Answer:

5446.8 J

Explanation:

From the question given above, the following data were obtained:

Mass (M) = 50 g

Initial temperature (T₁) = 70 °C

Final temperature (T₂) = 192.4 °C

Specific heat capacity (C) = 0.89 J/gºC

Heat (Q) required =?

Next, we shall determine the change in the temperature. This can be obtained as follow:

Initial temperature (T₁) = 70 °C

Final temperature (T₂) = 192.4 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 192.4 – 70

ΔT = 122.4 °C

Finally, we shall determine the heat required to heat up the block of aluminum as follow:

Mass (M) = 50 g

Specific heat capacity (C) = 0.89 J/gºC

Change in temperature (ΔT) = 122.4 °C

Heat (Q) required =?

Q = MCΔT

Q = 50 × 0.89 × 122.4

Q = 5446.8 J

Thus, the heat required to heat up the block of aluminum is 5446.8 J

5 0
3 years ago
Which temperature is warmer 0° F or 0°C
Y_Kistochka [10]

Answer:

0 degree C

Explanation:

0 degree C = 32 degree F

0 degree F = -17.7778 degree C

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