Answer:
Is better use the Benedict's test by the increase in the amount of the products if the enzyme is a reductase
Explanation:
The Benedict's test works by the reaction of the reducing sugars with the ion cupric of the reactive. If the enzyme is a reductase (degrades polysaccharides into bi o monosaccharides), it should cut the polysaccharide bond and the products would react with the Benedict's cupric ion
I hope you undestand me
Answer:
12 átomos de oxígeno hay presentes
Explanation:
Basados en la reacción:
6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂
<em>6 moles de agua producen 1 mol de glucosa</em>
<em />
Si reaccionan 12 moleculas de agua, se producirán:
12 moleculas H₂O * (1 mol C₆H₁₂O₆ / 6 mol H₂O) =
2 moléculas de glucosa se producen.
Como cada molécula de glucosa tiene 6 átomos de oxígeno:
2 moléculas C₆H₁₂O₆ * (6 átomos Oxígeno / 1 molécula C₆H₁₂O₆) =
<h3>12 átomos de oxígeno hay presentes</h3>
Answer:
molarity of the KI solution = 0.04 mol/L
Explanation:
Molarity (M) is the concentration of a solution expressed as the number of moles of solute per liter of solution.
The law that we can applied to calculate the M is:
M = n / V
n - number of moles
V- volume of the solution (liters)
Then insert in the equation the values from the question;
M = 0.082 mol / 2.03 L = 0.04 mol/L
Answer:
D
Explanation: iIt is a neutralization reaction and neutralization reaction is a reaction between and acid and base to give salt and water. In the question above, Ca(OH)2 is the base and HCl is the acid, Ca(Cl)2 is the salt and H2O.
Answer:
Molality = 1.13 m
Explanation:
Molality is defined as the moles of the solute present in 1 kilogram of the solvent.
Given that:
Mass of 
= 26.5 g
Molar mass of = 32.04 g/mol
The formula for the calculation of moles is shown below:
Thus,
Mass of water = 735 g = 0.735 kg ( 1 g = 0.001 kg )
So, molality is:
<u>Molality = 1.13 m</u>
