Answer:
-1
Step-by-step explanation:
This all comes down to the substitution. I am assuming that (4x2) is meant to be 4x^2 so I will solve as that.
4(-2)^2 = 4(4) = 16
4(-2) = - 8
-2(3)^2 = -2(9) = -18
3(3) = 9
16-8-18+9= -1
I think the coordinates are 1, 10 but not positive because if you graph it you can see a kite in it so make the point close to 4,10
Answer: 
Step-by-step explanation:
The standard form of thr number is 11.651
Hello! Lets solve this :)
So for the first question :
h(t) = -16t^2 + 150
h(0)= -16 (0)^2 + 150
h(0)= -16(0) + 150
h(0)= 0 + 150
h(0)= 150 feet
Second question
We need to find here the time when the ball hit the ground; or when the height h(t) is 0.
In equation form
h(t) --> 0=16t^2 + 150
16t^2 = 150
t^2=150/16
t= <span>√150/16
t= 5</span><span>√6/4
t= 5 (2.45)/4
t= 3.06 seconds
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Hope this helps! If you have any other questions or would like further explanation just let me know! :)
