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ArbitrLikvidat [17]
2 years ago
13

If mass (M), Velocity (V) and length (L) are considered as fundamental quantities in certain system of unit. Find the dimensiona

l formula for force.
Physics
1 answer:
Mama L [17]2 years ago
3 0

Answer:

Explanation:

MLT^-2

.....

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Why can't 41 be represented in a binary table?
Airida [17]

Answer:

I think it is but I don't know for sure

Explanation:

41 101001

41 is 101001 on the binary table i think

8 0
3 years ago
If the energy from the light is captured and stored by the surface without being reflected or transmitted, then it has been ____
vekshin1
A. ABSORBEDDDDDDDDDDDDDDDDDD
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4 years ago
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In which year was the first Badminton game played in the Olympics
Kisachek [45]
Year 1972
if I'm not wrong :)
4 0
3 years ago
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Which of the following was an effect of the French Revolution?
lozanna [386]

Answer: C. the elimination of special privileges for members of the first and second estates

Explanation:

The French Revolution was a period of political change in France. The French Revolution led to the proclamation of the first French Republic, radical political and social change, creation of constitutional monarchy, formation of the French consulate etc.

From the options given, the effect of the French Revolution was the the elimination of special privileges for members of the first and second estates. Therefore, the correct option is C.

5 0
3 years ago
Suppose an event is measured to be at a = (0,-2, 3, 5) in one reference frame. Find the components of this event in another refe
LenaWriter [7]

Answer:

The components of the moving frame is (8.07c, -2, 3, 9.493)

Solution:

As per the question:

Velocity of moving frame w.r.t original frame v_{m} 0.85c

Point 'a' of an event in one reference frame corresponds to the (x, y, z, t) coordinates of the plane

a = (0, - 2, 3, 5)

Now, according the the question, the coordinates of moving frame, say (X, Y, Z, t'):

New coordinates are given by:

X = \frac{x - v_{m}t}{\sqrt{1 - \frac{v_{m}^{2}}{c^{2}}}}

X = \frac{0 - 0.85c\times 5}{\sqrt{1 - \frac{(0.85c)^{2}}{c^{2}}}}

X = 8.07 c

Now,

Y = y = - 2

Z = z = 3

Now,

t' = \frac{t - \frac{vx}{c}^{2}}{\sqrt{1 - (\frac{v}{c})^{2}}}

t' = \frac{5 - 0}{\sqrt{1 - (\frac{0.85c}{c})^{2}}} = 9.493 s

4 0
4 years ago
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