The reason we should store phosphorous in water is because it will ignite on contact with air
Hey there,
That is because, chlorine is more reactive than Bromine.
**Important note: The lower you go in the periodic table of elements, the less reactive the elements become.
Hope this helps :))
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C. Heat answer correct that
Answer:
Without doing any calculations it is possible to determine that silver chromate is more soluble than <u>C,D ,</u> and silver chromate is less soluble than <u>none</u> .
It is not possible to determine whether silver chromate is more or less soluble than <u>A,B</u> by simply comparing Kspvalues
Explanation:
For this kind of question you need to obtain the balanced equation for the solubility, first, you will write the dissociation equation for every molecule, obtaining the ions in which it dissociates. Then you substitute in the Kps equation
![A_{n}B_{m} -> nA^{m+}+mB^{n-} \\K_{s}=[A^{m}]^{n}[B^{n}]^{m}](https://tex.z-dn.net/?f=A_%7Bn%7DB_%7Bm%7D%20-%3E%20nA%5E%7Bm%2B%7D%2BmB%5E%7Bn-%7D%20%5C%5CK_%7Bs%7D%3D%5BA%5E%7Bm%7D%5D%5E%7Bn%7D%5BB%5E%7Bn%7D%5D%5E%7Bm%7D)
Considering the corresponding stoichiometry you'll substitute in your dissociation equations as follow.
![Ag_{2}CrO_{4}(s)->2Ag^{+}(aq)+CrO_{4} ^{2-}\\ s ->2s+s\\s->[2s]^{2}[s]=4s^{3} \\\\A) PbF_{2}(s)->Pb^{2+} (aq)+2F^{-}\\s->s+2s\\s->[s][2s]^{2}=4s^{3}\\\\\\B)Ag_{2}SO_{3}(s)->2Ag^{+}(aq)+SO_{3} ^{2-}\\ s ->2s+s\\s->[2s]^{2}[s]=4s^{3} \\\\\\C)NiCO_{3}(s)->Ni^{2+}(aq)+CO_{3} ^{2-}\\ s ->s+s\\s->[s][s]=s^{2} \\\\\\D)AgCl(s)->Ag^{+}(aq)+Cl^{-}(aq)\\ s ->s+s\\s->[s][s]=s^{2} \\](https://tex.z-dn.net/?f=Ag_%7B2%7DCrO_%7B4%7D%28s%29-%3E2Ag%5E%7B%2B%7D%28aq%29%2BCrO_%7B4%7D%20%5E%7B2-%7D%5C%5C%20%20%20%20%20%20%20%20s%20%20-%3E2s%2Bs%5C%5Cs-%3E%5B2s%5D%5E%7B2%7D%5Bs%5D%3D4s%5E%7B3%7D%20%20%5C%5C%5C%5CA%29%20%20PbF_%7B2%7D%28s%29-%3EPb%5E%7B2%2B%7D%20%28aq%29%2B2F%5E%7B-%7D%5C%5Cs-%3Es%2B2s%5C%5Cs-%3E%5Bs%5D%5B2s%5D%5E%7B2%7D%3D4s%5E%7B3%7D%5C%5C%5C%5C%5C%5CB%29Ag_%7B2%7DSO_%7B3%7D%28s%29-%3E2Ag%5E%7B%2B%7D%28aq%29%2BSO_%7B3%7D%20%5E%7B2-%7D%5C%5C%20%20%20%20%20%20%20%20s%20%20-%3E2s%2Bs%5C%5Cs-%3E%5B2s%5D%5E%7B2%7D%5Bs%5D%3D4s%5E%7B3%7D%20%20%5C%5C%5C%5C%5C%5CC%29NiCO_%7B3%7D%28s%29-%3ENi%5E%7B2%2B%7D%28aq%29%2BCO_%7B3%7D%20%5E%7B2-%7D%5C%5C%20%20%20%20%20%20%20%20s%20%20-%3Es%2Bs%5C%5Cs-%3E%5Bs%5D%5Bs%5D%3Ds%5E%7B2%7D%20%20%5C%5C%5C%5C%5C%5CD%29AgCl%28s%29-%3EAg%5E%7B%2B%7D%28aq%29%2BCl%5E%7B-%7D%28aq%29%5C%5C%20%20%20%20%20%20%20%20s%20%20-%3Es%2Bs%5C%5Cs-%3E%5Bs%5D%5Bs%5D%3Ds%5E%7B2%7D%20%20%5C%5C)
IIn this case, the silver chromate has a Kps of
, same as the compound in options A and B, comparing these numbers you can't determine which one is bigger. Finally, options C and D have a kps of
, this value is smaller than silver chromate's kps.
I hope you find this information useful! good luck!
Taking into account the reaction stoichiometry, 2 moles of CaO are required to react with 2 moles of Ca(OH)₂.
<h3>Reaction stoichiometry</h3>
In first place, the balanced reaction is:
CaO + H₂O → Ca(OH)₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- CaO: 1 mole
- H₂O: 1 mole
- Ca(OH)₂: 1 mole
<h3>Moles of CaO required</h3>
The following rule of three can be applied: If by stoichiometric reaction 1 mole of Ca(OH)₂ is produced by 1 mole of CaO, 2 moles of Ca(OH)₂ are produced by how many moles of CaO?

moles of CaO= 2 moles
Finally, 2 moles of CaO are required to react with 2 moles of Ca(OH)₂.
Learn more about the reaction stoichiometry:
brainly.com/question/24741074
brainly.com/question/24653699
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