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The volume of O₂ produced: 84.6 L
<h3>Further explanation</h3>
Given
7.93 mol of dinitrogen pentoxide
T = 48 + 273 = 321 K
P = 125 kPa = 1,23365 atm
Required
Volume of O₂
Solution
Decomposition reaction of dinitrogen pentoxide
2N₂O₅(g)→4NO₂(g)+O₂ (g)
From the equation, mol ratio N₂O₅ : O₂ = 2 : 1, so mol O₂ :
= 0.5 x mol N₂O₅
= 0.5 x 7.93
= 3.965 moles
The volume of O₂ :

Decreasing temperature and increasing pressure
Avogadro's number is the number of atoms in one mole of a substance. The number is 6.022 x 10^23 atoms/mol. So, if you have 1 mole of carbon atoms, there will be 6.022 x 10^23 atoms in that sample.
Hope this helps