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zysi [14]
3 years ago
14

The 3 in 4p3 represents:

Chemistry
2 answers:
Ad libitum [116K]3 years ago
5 0

Answer: b. the number of electrons

Explanation: 4p^3

1. 4 is the principal quantum number which describes the size of the orbital. It is represented by n.

2. The electrons are present in p sub shell also called as azimuthal quantum Number: This quantum number describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For p orbital, l=1.

3. The p subshell contains 3 electrons.


Marrrta [24]3 years ago
3 0
B) the number of electrons
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What is the frequency of the light with a wavelength of 4.90x10^-7 m
docker41 [41]

Answer: 6.12\times 10^{14} Hz

Explanation: Recall the formula for the speed of light is

c=\lambda v

where c is the speed of light,\lambda is the wavelength, and v is the frequency. Assuming this takes place in a vacuum, c=3.00\times 10^8 m/s. Now we can solve for frequency

c=\lambda v

3.00\times 10^8 = 4.90\times 10^{-7}\cdot v

v = \frac{3.00\times 10^8}{4.90\times 10^{-7}}

v =6.12\times 10^{14} (rounding to 3 sig figs)

Thus, the frequencyis 6.12\times 10^{14} Hz.

6 0
3 years ago
Identify the substances that are likely to dissociate in water
weqwewe [10]

Answer:

Acetic Acid (HC2H3O2) dissolves in water, but only partially dissociates into ions.

8 0
4 years ago
Does solubility have any unit? Answer properly​
AVprozaik [17]

Answer:

Water solubility is a measure of the amount of chemical substance that can dissolve in water at a specific temperature. The unit of solubility is generally in mg/L (milligrams per liter) or ppm (parts per million). You can often find it in the section 9 of a safety data sheet (SDS).

Explanation:

7 0
3 years ago
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Why do covalent bonds not involve the transfer of electrons
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Covalent bonds do not involve electron transfer because in covalent bonds, the electrons are shared between the atoms to form the molecule rather than being transferred to form ions as it is in the case of ionic bonds.<span />
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3 years ago
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Suppose 10.0 mL of 2.00 MNaOH is added to (a) 0.780 L of pure water and (b) 0.780 L of a buffer solution that is 0.682 Min butan
katrin2010 [14]

Answer:

a) pH will be 12.398

b) pH will be 4.82.

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The new concentration of /NaOH will be:

molarity=\frac{molesofsolute}{volumeofsolution}=\frac{0.02}{0.79}=0.025M

the [OH⁻] = 0.025

pOH = -log [OH⁻] = 1.602

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b) The buffer has butanoic acid and butanoate ion.

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pH=pKa+log\frac{[salt]}{[acid]}

pKa=-logKa=-log(1.5X10^{-5})=4.82

ii) on addition of base the pH will increase.

8 0
4 years ago
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