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stepan [7]
2 years ago
5

If a train travel from Addis Ababa to Dire Dawa at a constant velocity of 400Km/hr and the to Djibouti at a constant velocity of

V. if the average velocity of 520Km/hr then what is the value of V?----------------
Physics
1 answer:
madreJ [45]2 years ago
4 0

The value of V is 640 km/hr.

<h3>What is Average velocity?</h3>

Average velocity is the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs.

To calculate the value of V from the question, we use the formula below.

  • V' = (V+U)/2............ Equation 1

Making V the subject of the equation

  • V = 2V'-U.............. Equation 2

From the question,

⇒ Given:

  • V' = 520 km/hr
  • U = 400 km/hr

Substitute these values into equation 2

  • V = (520×2)-400
  • V = 640 km/hr

Hence, the value of V is 640 km/hr.

Learn more about average velocity here: brainly.com/question/4931057

#SPJ1

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While playing a video game on your laptop, the laptop gets very hot. Which Thermodynamics Law does this exemplify?
Ksivusya [100]

Answer

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3 0
3 years ago
A frog is at the bottom of a 17-foot well. Each time the frog leaps, it moves up 3 feet. If the frog has not reached the top of
docker41 [41]

Answer:

The frog takes 8 jumps to reach top of well

Explanation:

Given data

Frog at bottom=17 foot

Each time frog leaps 3 feet

Frog has not reached the top of the well, then the frog slides back 1 foot

To Find

Total number of leaps the frog needed to escape from well

Solution

in 1 jump distance jumped=3+(-1)

                                           =2 feet

                                           =2×1 feet

The "-1" is because the frog goes back

Now After 2 jumps the distance jumped as:

                     Distance Jumped=2+2

                     Distance Jumped=2*2

                                                   =4 feet

Similarly after 7 jumps

                    Distance Jumped=2+2+......+2

                    Distance Jumped=2*7

                                                 =14 feet

Now after 8th jump the frog climbs but doesnot slide back as it is reached to the top of well.

So

              Distance Jumped=(Distance Jumped after 7 jumps)+3

                                           =14+3

                                           =17 feet

The frog takes 8 jumps to reach top of well                

7 0
3 years ago
A dolphin in an aquatic show jumps straight up out of the water at a velocity of 15.0 m/s. (a) List the knowns in this problem.
astra-53 [7]

Answer:

a)

Y0 = 0 m

Vy0 = 15 m/s

ay = -9.81 m/s^2

b) 7.71 m

c) 3.06 s

Explanation:

The knowns are that the initial vertical speed (at t = 0 s) is 15 m/s upwards. Also at that time the dolphin is coming out of the water, so its initial position is 0 m. And since we can safely assume this happens in Earth, the acceleration is the acceleration of gravity, which is 9.81 m/s^2 pointing downwards

Y(0) = 0 m

Vy(0) = 15 m/s

ay = -9.81 m/s^2 (negative because it points down)

Since acceleration is constant we can use the equation for uniformly accelerated movement:

Y(t) = Y0 + Vy0 * t + 1/2 * a * t^2

To find the highest point we do the first time derivative (this is the speed:

V(t) = Vy0 + a * t

We equate this to zero

0 = Vy0 + a * t

0 = 15 - 9.81 * t

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0 = Y0 + Vy0 * t + 1/2 * a * t^2

0 = 0 + 15 * t - 1/2 * 9.81 t^2

0 = 15 * t - 4.9 * t^2

0 = t * (15 - 4.9 * t)

t1 = 0 This is the moment it jumped into the air

0 = 15 - 4.9 * t2

15 = 4.9 * t2

t2 = 3.06 s This is the moment when it falls again.

3.06 - 0 = 3.06 s

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liberstina [14]

Answer:

Its not A..

Explanation:

I chose A - was incorrect

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