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Rom4ik [11]
3 years ago
12

Two converging lenses, one with f = 4.0 cm and the other with f = 37 cm , are made into a telescope. What is the length of this

telescope?
What is the magnification of this telescope?
Physics
1 answer:
d1i1m1o1n [39]3 years ago
8 0

Answer:

The length and the magnification of this telescope are 41 cm and 0.108.

Explanation:

Given that,

Focal length of first lens f= 4.0 cm

Focal length of other lens f'= 37 cm

We need to calculate the length of the telescope

Using formula of length

L=f+f'

Put the value into the formula

L=4+37=41 cm

We need to calculate the magnification of the telescope

Using formula of the magnification

m=\dfrac{f}{f'}

Put the value into the formula

m=\dfrac{4}{37}

m=0.108

Hence, The length and the magnification of this telescope are 41 cm and 0.108.

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Answer:

The (s) indicates that the state of matter for NaHCO3 is solid.

Explanation:

When a chemical reaction is written, the state of matter for each components of the reactants and products are mentioned in brackets along with their names or formulas.

For example, NaHCO3 has (s) mentioned in the brackets. The s shows that the state of matter for NaHCO3. (l) represents liquid format. (g) represents that the state of matter is gas.

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Answer:

(A) a heuristic

Explanation:

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3 0
3 years ago
A 4.79 g bullet moving at 642.3 m/s penetrates a tree trunk to a depth of 4.35 cm. Use work and energy considerations to find th
vladimir1956 [14]

Answer:

Force, F=2.27\times 10^4\ N

Explanation:

Given that,

Mass of the bullet, m = 4.79 g = 0.00479 kg

Initial speed of the bullet, u = 642.3 m/s

Distance, d = 4.35 cm = 0.0435 m

To find,

The magnitude of force required to stop the bullet.

Solution,

The work energy theorem states that the work done is equal to the change in its kinetic energy. Its expression is given by :

F.d=\dfrac{1}{2}m(v^2-u^2)

Finally, it stops, v = 0

F.d=-\dfrac{1}{2}m(u^2)

F=\dfrac{-mu^2}{2d}

F=\dfrac{-0.00479\times (642.3)^2}{2\times 0.0435}

F = -22713.92 N

F=2.27\times 10^4\ N

So, the magnitude of the force that stops the bullet is 2.27\times 10^4\ N

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Find the radioactivity of a 1 g sample of 226Ra given that <img src="https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D1620" id="TexFormul
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Answer:

Explanation:

No of atoms of Ra in 1 g of sample = 6.023 x 10²³ / 226

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disintegration constant λ = .693 / 5.1 x 10¹⁰

radioactivity dn / dt = λN

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= .3614 x 10¹¹ per sec

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